HELP WILL MARK BRAINLIEST TO WHOEVER ANSWERS !!

Anyone have any idea what it could be?

Ronch [10]

The answer is B because 90 to 30 is 3 over 2

4 0

3 years ago

How do u do this please help!!

aev [14]

Answer:

Step-by-step explanation:

1 gallon = 4 quarts

5 gallons 2 quarts 1 pint = 4 gallons 6 quarts 1 pint

(5 gallons 2 quarts 1 pint) - (1 gallon 3 quarts)

= (4 gallons 6 quarts 1 pint) - (1 gallon 3 quarts)

= 3 gallons 3 quarts 1 pint

7 0

3 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

Jan spent the day at the mall. She came home with $9.50. She spent $5.25 on earrings and 3 times that amount on a shirt. How muc

ki77a [65]

Answer:

She took $30.50 to the mall originally

Step-by-step explanation:

Let us solve the problem step by step

∵ She spent $5.25 on earrings

∵ The price of the shirt is 3 times the price of the earrings

∴ The price of the shirt = 3 × 5.25 = 15.75

∴ She spent $15.75 on the shirt

Find her total spending in the mall by adding the prices of earrings and the shirt

∴ She spent = 5.25 + 15.75 = 21

∴ She spent $21 on the mall

∵ She came home with $9.50

∵ She spent $21 on the mall

- Add them to find her original amount of money

∴ She took = 21 + 9.50 = 30.50

∴ She took $30.50 to the mall originally

5 0

3 years ago

Help please

ddd [48]

Answer:

B. When the peak temperature is 40°C, 72 units of electricity are used on average.

Step-by-step explanation:

We see the relationship is closer to linear in the interval 30 to 40

<u>Approximate points:</u>

(30, 34) and (34, 54)

<u>The slope of the line:</u>

m = (54 - 34)/(34- 30) = 20/4 = 5

y - 34 = 5(x - 30)
y = 5x - 116

<u>At x = 40, the value of y would be:</u>

y = 5*40 - 116 = 84

The closet option is B

7 0

2 years ago