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3 years ago

Find the unknown side length of the rectangle is 3 2/3 and if the area is 11m2

Mathematics

1 answer:

patriot [66]3 years ago

7 0

Answer:

The width of the rectangle given is equal to 3m.

Step-by-step explanation:

In order to solve this question we need to know that the areas of the rectangle is equal to $A_{rectangle} = (l)(w)$ , where "l" is length and "w" is width. So know in order to solve this question we would have to find out the unknown width by using area and the length of the triangle. Based on the formula I wrote down earlier we can understand the following.....

$A_{rectangle} = (l)(w)$

$\frac{A_{rectangle} }{l} = \frac{(l)(w)}{l}$

$w = \frac{A_{rectangle} }{l}$

Just now we found out the formula that we can use to solve for the width when we know the area and the length of the rectangle. Now in order to get the answer we just have to plug in the values we know, and we get........

$w = \frac{A_{rectangle} }{l}$

$w = \frac{11m^{2} }{(3\frac{2}{3}m )}$

$w = 3m$

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Step-by-step explanation:

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A random sample of 85 sixth-graders in a large city take a course designed to improve scores on a reading comprehension test. Ba

BartSMP [9]

Answer:

$12.6 < \mu < 14.8$

For this case we can find the margin of error like this:

$ME= \frac{14.8-12.6}{2}= 1.1$

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And now with the margin of error we can find the sample mean with any of the two following ways:

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So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

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We know that the confidence interval is given by:

$12.6 < \mu < 14.8$

For this case we can find the margin of error like this:

$ME= \frac{14.8-12.6}{2}= 1.1$

Since we need to divide the width of the interval by 2.

And now with the margin of error we can find the sample mean with any of the two following ways:

$12.6 +1.1=13.7$

$14.8-1.1=13.7$

So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

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3 years ago

An auto mechanic ordered eight car spark plugs and four truck spark plugs. Car spark plugs cost $.75, and truck spark plugs cost

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3 years ago

18n squared + 57n -10

aniked [119]

Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way

Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
=-180
find the sum =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.

so (n-3)(n+60)
divide by a in this case it 18
so (n-3)(n+60)
18 18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n-3)(n-3)
 18 10
 at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"

=(18n-3)(10n-3)

therefore your answer is (18n-3)(10n-3)
I hoped this helped :)

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3 years ago