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s2008m [1.1K]
3 years ago
12

How to solve system by substitution X+y=10 X-y=2

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

x = 6 , y = 4

Step-by-step explanation:

Solve the following system:

{x + y = 10

x - y = 2

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for y:

{x + y = 10

x - y = 2

Hint: | Solve for y.

Subtract x from both sides:

{y = 10 - x

x - y = 2

Hint: | Perform a substitution.

Substitute y = 10 - x into the second equation:

{y = 10 - x

2 x - 10 = 2

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{y = 10 - x

2 x - 10 = 2

Hint: | Isolate terms with x to the left hand side.

Add 10 to both sides:

{y = 10 - x

2 x = 12

Hint: | Solve for x.

Divide both sides by 2:

{y = 10 - x

x = 6

Hint: | Perform a back substitution.

Substitute x = 6 into the first equation:

{y = 4

x = 6

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = 6 , y = 4

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Find the unit vector in the direction of (4,-4). Write your answer in component form. Do not approximate any numbers in your ans
aniked [119]

Answer:

(\frac{1}{\sqrt{2} }, \frac{-1}{\sqrt{2} }  )

Step-by-step explanation:

The unit vector for a nonzero vector, say u, in the direction of u is given by:

û = \frac{u}{|u|}             ---------------(i)

Where;

|u| = magnitude of vector u

From the question;

u = (4, -4)

First let's calculate the magnitude of u as follows;

|u| = \sqrt{(4)^2 + (-4)^2}

|u| = \sqrt{16 + 16}

|u| = \sqrt{32} = 4\sqrt{2}

Now, substitute u and |u| into equation (i) as follows;

û = \frac{(4, -4)}{4\sqrt{2} }

û = (\frac{4}{4\sqrt{2} }, \frac{-4}{4\sqrt{2} }  )

û = (\frac{1}{\sqrt{2} }, \frac{-1}{\sqrt{2} }  )

Therefore, the unit vector is (\frac{1}{\sqrt{2} }, \frac{-1}{\sqrt{2} }  )

7 0
3 years ago
This is what i need help with thanks​
lawyer [7]
B
Hope this helped you
7 0
3 years ago
Read 2 more answers
Express the product in simplest form.
Dmitry [639]

The product in simplest form is (x - 4)

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{8}{2x+8} \times \frac{x^2-16}{4}

We have to find the product in simplest form

In the given expression,

2x + 8 = 2(x+ 4)

We know that,

a^2-b^2=(a+b)(a-b)

Therefore,

x^2-16 = x^2-4^2 =(x+4)(x-4)

Substitute these in given expression

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4}

Cancel the common factors,

\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4} = x - 4

Thus the product in simplest form is (x - 4)

8 0
3 years ago
Which statement is true about the given information?
Lubov Fominskaja [6]

Answer

∴ The true statement is Answer:

The true statement is BD ≅ CE  ⇒ 3rd answer

Step-by-step explanation:

- There is a line contained points B , C , D , E

- All points are equal distance from each other

- That means the distance of BC equal the distance of CD and equal

 the distance of DE

∴ BC = CD = DE

- That means the line id divided into 3 equal parts, each part is one

  third the line

∴ BC = 1/3 BE

∴ CD = 1/3 BE

∴ DE = 1/3 BE

∵ BC = CD

∴ C is the mid-point of BD

∴ BC = 1/2 BD

∵ CD = DE

∴ D is the mid-point of DE

∴ CD = 1/2 CE

- Lets check the answers

* BD = one half BC is not true because BC = one half BD

* BC = one half BE is not true because BC = one third BE

* BD ≅ CE is true because

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 CE = CD + DE

 BC ≅ DE and CD is common

 then BD ≅ CE

* BC ≅ BD is not true because BC is one half BD

∴ The true statement is BD ≅ CE

plz mark me brainliest

5 0
2 years ago
the width of a rectangle is 4 less than half the length. if l represents the length, wich equation could be used to find the wid
torisob [31]
w=\dfrac{1}{2}l-4
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