All categories

3 years ago

Determine the simple interest that is accured on $.5500 for five years at a rate of 8.5%.

Mathematics

1 answer:

Alex73 [517]3 years ago

4 0

Answer:

$2337.5

Step-by-step explanation:

5500x5x8.5/100

=$2337.5

You might be interested in

You can jog around your block twice and the park once in 10 minutes. You can jog around your block twice and the park 3 times in

exis [7]

2x + y = 10
2x + 3y = 22

Please consider marking this answer as Brainliest to help me advance, and let me know if you need any clarifications.

4 0

3 years ago

What is the equation of this line?

QveST [7]

Answer:

y = (1/2)x - 3 Answer A is closest.

Step-by-step explanation:

Two points on the line are (0, -3) and (4, -1). Notice that I've intentionally chosen "nice" points whose coordinates are integers; this makes the math easier. The point (1, -5/2) is also on the line if you want to use it, but the math's a bit more complicated.

Going from (0, -3) to (4, -1), x increases by 4 and y increases by 2. Hence, the slope of this line is m = rise / run = 2/4, or m = 1/2.

The slope-intercept formula for the equation of a straight line is the most convenient to use here, since we can tell immediately from the graph that the y-intercept is (0, -3):

y = (1/2)x - 3

Answer A should be y = (1/2)x - 3 for improved legibility. 1 2 x is not correct as a way to express (1/2)x.

6 0

3 years ago

Read 2 more answers

What are the dependent (y) and the independent (x) variables?

Alexandra [31]

Answer:

i donk know and i dont understand the question

Step-by-step explanation:

7 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$