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Oduvanchick [21]
3 years ago
5

How are the power rules for quotients and products similar? How are they different? Refer specifically to the way that the rule

is proven to be true.
Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0
Power rules for both quotient and product sums are useful to simplify large exponential form (of the same base)

The difference is in the rule. For quotient sum, the powers are subtracted, while for product sum, the powers are added up.

An example for quotient sum
\frac{7^{13} }{7^{8} } = \frac{7*7*7*7*7*7*7*7*7*7*7*7*7}{7*7*7*7*7*7*7*7*7*7}
Using the principle of simplifying fractions, we can cancel out ten 7s from both numerator and denominator, leaving us with only three 7s on the numerator which gives us 7^{3}. This working out could be simplified by doing 7^{13-10}= 7^{3}

An example for product sum
9^{5}* 9^{6} =(9*9*9*9*9)*(9*9*9*9*9*9)= 9^{11}. There is a total of eleven 9s if we were to work out the product sum the long way. This could be simplified by doing 9^{5+6} = 9^{11}
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A store receives tomatoes in boxes of 40 tomatoes each. About 4 tomatoes per box cannot be sold due to damage. Write an algebrai
monitta

Answer:

40b - 4b    or 36 b

Step-by-step explanation:

No. of tomatoes in each box = 40

No. of box shipped = b

No. of tomatoes in those b box = b*No. of tomatoes in each box = 40b

No. of tomatoes damaged in each box = 4

No. of box shipped = b

No. of tomatoes damaged in those b box = b*No. of tomatoes damaged in each box = 4b

Thus, total no. of tomatoes that can be sold by store = No. of tomatoes in those b box - No. of tomatoes damaged in those b box  = 40b - 4b

Algebraic expression to express the no. of tomatoes that can be sold from those b box is

40b - 4b = 4b(10-1) = 4b(9) = 36b (Answer)

3 0
3 years ago
What is the area of a circle whose equation is (x-3)² + (y + 1) ² =81?
kupik [55]
Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle: 

\frac{(x-x_{1})^2}{r^2}+ \frac{(y-y_{1})_^2}{r^2}=1

Where (x_{1}, y_{1}) is the centre of the circle. In this case, we don't need to know the centre. Just the radius. 

Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81. 

\frac{(x-3)^2}{81}+ \frac{(y+1)^2}{81}=1

Great! We now know the radius of the circle. It is \sqrt{81} because it is the bottom fraction. Now we know that the radius is 9. 

So now lets input this into the area of circle formula: 

A=πr^2 

Now we insert our radius. 

A=9^2π 

=A=81π 

You can convert that into a decimal if you wish. 

Hope this helped!

~Cam943, Moderator
4 0
3 years ago
A coat with an original price tag of $400 was marked down by 40%. You have a coupon good for an additional 25% off. What is the
VMariaS [17]

Answer:

65%=$260

Step-by-step explanation:

40%+25%=65%

65% of 400

65/100*400

=$260

7 0
2 years ago
Read 2 more answers
Sarah is saving money to buy a microscope. She has saved $25 so far. That's 1/3 of the
seropon [69]

Answer:

X = $75

Step-by-step explanation:

X=total cost

x* (1/3) =$25

multiply by 3 on both sides

x=$75

4 0
2 years ago
What is the difference between a constant and a variable
denis-greek [22]

Answer:

A constant is a number that stays the same. A variable is number that doesn't remain the same.

7 0
3 years ago
Read 2 more answers
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