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svet-max [94.6K]
3 years ago
8

What is the equation of the line that passes through the point (4,7) and has a slope of o?

Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

The equation of the line that passes through the point (4,7) and has a slope of 0 will be:

  • y=7

Step-by-step explanation:

As we know the equation of a line in a slope-intercept form of an equation is

y = mx + b

Here,

  • m is the slop
  • b is the y-intercept

so

substituting the point (4,7) and slope m=0

y = mx + b

7=0(4)+b

7=0+b

b=7

Therefore, the equation of the line that passes through the point (4,7) and has a slope of 0 will be:

y = mx + b

y=0x+7

y=7

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Solve the inequality 2x + 8 < 5x − 4.
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3 years ago
( – 1, – 5) 7x+2y=13, 4x+4y=14
serious [3.7K]

Answer:

{x,y} = {6/5,23/10}

Step-by-step explanation:

 [1]    7x + 2y = 13

  [2]    4x + 4y = 14  <---------- linear equations given

Graphic Representation of the Equations : PICTURE
2y + 7x = 13        4y + 4x = 14  

Solve by Substitution :

// Solve equation [2] for the variable  y

[2]    4y = -4x + 14

[2]    y = -x + 7/2

// Plug this in for variable  y  in equation [1]

  [1]    7x + 2•(-x +7/2) = 13

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// Solve equation [1] for the variable  x

  [1]    5x = 6

  [1]    x = 6/5

// By now we know this much :

   x = 6/5

   y = -x+7/2

// Use the  x  value to solve for  y

   y = -(6/5)+7/2 = 23/10

// Plug this in for variable  y  in equation [1]

 [1]    7x + 2•(-x +7/2) = 13

  [1]    5x = 6

// Solve equation [1] for the variable  x

 [1]    5x = 6

[1]    x = 6/5

// By now we know this much :

   x = 6/5

   y = -x+7/2

// Use the  x  value to solve for  y

  y = -(6/5)+7/2 = 23/10

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