What is the equation of the line that passes through the point (4,7) and has a slope of o?

Mathematics

1 answer:

Svetlanka [38]3 years ago

5 0

Answer:

The equation of the line that passes through the point (4,7) and has a slope of 0 will be:

$y=7$

Step-by-step explanation:

As we know the equation of a line in a slope-intercept form of an equation is

$y = mx + b$

Here,

m is the slop

b is the y-intercept

substituting the point (4,7) and slope m=0

$y = mx + b$

$7=0(4)+b$

$7=0+b$

$b=7$

Therefore, the equation of the line that passes through the point (4,7) and has a slope of 0 will be:

$y = mx + b$

$y=0x+7$

$y=7$

You might be interested in

Please Help me!!

yanalaym [24]

The answer would be E= 27 miles
You would start out by figuring out how many hours it would take him to swim by dividing 6/2 to get 3 then you would find out how long it would take him to run by dividing 15/6 to get 2.5 and you would add that to the 3 to get 5.5 and subtract that by 7 to get 1.5 which is how long he will have to complete leg 3 so you would take 18x1.5 to get 27 mph

3 0

3 years ago

Emily is observing the velocity of a cyclist at different times. After four hours, the velocity of the cyclist is 14 km/h. After

lina2011 [118]

Assume that Emily starts from rest so that the velocity is zero at 0 hours.

Define the function v(t) for velocity in km/h, and t in hours.

Part A
From t=0 to t=4, v changes from 0 to 14.
Let v(t) = mt + b
The slope is
m = 14/4 = 3.5, and the y-intercept is
b = 0.
Therefore
v(t) = 3.5t, for 0 ≤ t ≤ 4

Fromt=4 to t=9, changes from 14 to 4.
Let v(t) = mt + b
The slope is
m = (4 - 14)/(9 - 4) = -2
Therefore
v = -2t + b
When t=4, v=14, therefore
14 = -2*4 + b = -8 + b
22 = b
v(t) = -2t + 22, for 4 < t ≤ 9.

Answer:
The equation for the velocity is
v(t) = 3.5t, 0 ≤ t ≤ 4
= -2t + 22, 4 < t ≤ 9

Part B
The equation for velocity is a piecewise function that is graphed as shown below. If we assume that the second part of the equation is valid at t=10, then
v(10) = -2*10 + 22 = 2 km/h