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horrorfan [7]
3 years ago
12

How many fourths are in one half? Please help me I'm confusion jk I'm confused thanks lol

Mathematics
1 answer:
RSB [31]3 years ago
6 0
1/4 + 1/4= 1/2

There are 2/4 in 1/2.

Hope this helps! :)
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What is the midpoint of the x-intercepts of f(x) = (x – 2)(x – 4)?
tatyana61 [14]
The x-intercepts are readily identified on the graph:  (2,0) and (4,0).  The midpoint of a line connecting those 2 points would be (3,0).
8 0
3 years ago
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A man is lying on the beach, flying a kite. He holds the end of the kite string at ground level and estimates the angle of eleva
Ulleksa [173]
This question uses trig

sin(55) = height/195

Therefore, height = 195sin(55) meters (just plug in calculator)
7 0
2 years ago
PLEASE HELP FASTTT!!!
nirvana33 [79]

Answer:

5 seconds

Step-by-step explanation:

Looking at your function (h(t) = -16t^2 + 48t + 160), I see that the peak height will be 196 feet, and that is achieved in 1.5 seconds.

h(1.5) = -16(1.5)^2 + 48(1.5) + 160

h(1.5) = -16(2.25)+ 48(1.5) + 160

h(1.5) = -36 + 48(1.5) + 160

h(1.5) = -36 + 72 + 160

h(1.5) = 36 + 160

h(1.5) = 196

Going down from that height, it would take 3.5 more seconds, so it would take 5 seconds in total

h(5) = -16(5)^2 + 48(5) + 160

h(5) = -16(25) + 48(5) + 160

h(5) = -400 + 48(5) + 160

h(5) = -400 + 240 + 160

h(5) = -400 + 400

h(5) = 0

8 0
3 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
2 years ago
The value of y varies directly with x2, and y = 150 when x = 5.<br> What is the value of y when x=3?
kow [346]
<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>
3 0
3 years ago
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