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Tamiku [17]
3 years ago
14

A pile of 55 coins consisting of nickels and dimes is worth $3.90 . Find the number of each.

Mathematics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

Answer:

Answer is: 32 nickels and 23 dimes.

x - number of nickels .

y -number of dimes.

two equations in two unknowns:

1) x + y = 55

2) 0,05x + 0,1y = 3,90.

nickel is a five-cent coin.

dime is a ten-cent coin.

solve equation 1) for x and substitute for x in equation 2)

x = 55 - y

0,05·(55 - y) + 0,1y = 3,902,75 - 0,05y + 0,1y = 3,90

0,05y = 1,15

y = 23.

x = 55 - 23 = 32.

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5 0
3 years ago
A drawer contains 12 brown socks and 12 black socks, all unmatched. A man takes socks out at random in the dark. 21. Required in
avanturin [10]

Answer:

6  socks

Step-by-step explanation:

What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.

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and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:

11/23

the final probability is the multiplication of these events:

(12/24) * (11/23)

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Now, to know how many you should get, we multiply the probability by the total number of socks, that is:

0.24 * 24 = 5.76

So you must take out at least 6 socks for the above to happen.

6 0
3 years ago
An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.
bija089 [108]

a_1=-9\\\\a_2=a_1-8\to a_2=-9-8=-17\\\\a_3=a_2-8\to a_3=-17-8=-25\\\\a_4=a_3-8\to a_4=-25-8=-33\\\\\text{The general term of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\a_1-first\ term\\d-common\ difference\\\\\text{We have}\ a_1=-9\ \text{and}\ d=-8.\ \text{Substitute:}\\\\a_n=-9+(n-1)(-8)=-9-8n+8=-8n-1\\\\\text{Put n = 43 and calculate}\ a_{43}\\\\a_{43}=-8(43)-1=-344-1=-345\\\\Answer:\ \boxed{?=-345}

4 0
3 years ago
Please help!!!!!!!!!!​
Minchanka [31]

Answer:

The overall average is 70 dollars for all weeks together

4 0
3 years ago
Read 2 more answers
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