Let the no be X and Y
acc to ques....
x-y=9 .........1
xy=162 ..........2
substituting value from 1 in 2 we get;
x=9+y
[9+y][y] = 162
y^2+9y = 162
y^2 + 9y - 162=0
y^2 + 18y - 9y - 162=0
y[y+18] + 9[y+18]=0
[y+9][y+18}
y= -9.................................3
y= -18......................................4
case 1 :
y= -9
x = 9-9=0
case 2:
y= -18
x= 9-18 = -9
Answer:
Step-by-step explanation:
Put x = 3, y = 2 and z = 5 to the given expression 
:
Answer:
Step-by-step explanation:
what is the problems ?
Answer:
Step-by-step explanation:
1/4 : 2 * 1/4 = 6 : x
0.25 : 2/4 = 6 : x
0.25 : 1/2 = 6 : x
0.25 : 0.5 = 6 : x
0.5 = 6 : x
x = 6 : 0.5
x = 12
