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Sergio039 [100]
3 years ago
10

Solve this system of equations 5x + 4y = 6 10x -2y = 7

Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

x = 4/5

y = 1/2

Step-by-step explanation:

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If the diameter of the sphere is 12cm what is the volume of the cylinder
german

r^{2}  \times \pi \times (h = height \: of \: the \: cilinder)
6 0
3 years ago
Levi’s Jeans Shop sells shorts for $21.75 each. Luke’s Jean Shop sells a two pairs of shorts for $43.50. Who has the best deal?
stiks02 [169]

Answer:

They both have equal deals.

Step-by-step explanation:

Levi's jeans shop- $21.75

Lukes jean shop- $21.75

If two of them cost $43.50, to find unit price divide two into 43.50

43.50/2=21.75


Hope it helps!

6 0
3 years ago
SOS PLZ IDK THIS VERY WELL NEED HELP
zaharov [31]

Answer:

1. a. 25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. b. Mark’s average < Jay’s average

Step-by-step explanation:

1. What is Mark’s slugging average?

The slugging average gives more weight to the multi-base hits (compared to single-base hits) in opposition with the batting average.

So, a single hit is worth 1 point, a double is worth 2 points, a triple 3 points and a homerun is worth 4 points.  It's a weighted average calculation.

Mark had 25 singles, 10 doubles, 3 triples and 10 homeruns during 140 presences 140 at bat.

25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. How does Mark's average compares to Jay's?

Let's first calculate Jay's slugging average then we'll be able to decide.

Jay had 10 singles, 6 doubles, 5 triples and 14 homeruns in 90 presences.

10 (1) + 6 (2) + 5 (3) + 14 (4) = 10+12+15+56 = 93 / 90 = 1.033

We can definitely say that Mark's slugging average (0.671) calculated above is lower than Jay's average (1.033).  So,

b. Mark’s average < Jay’s average

8 0
3 years ago
The time, in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters
Serhud [2]

Answer:

d=\dfrac{t^2}{a}

Step-by-step explanation:

The time  in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this  equation.

t = va

We need to find the expression for d in terms of t and a.

As velocity = distance/time

t=\dfrac{d}{t}a\\\\t^2=da\\\\d=\dfrac{t^2}{a}

So, the distance d is \dfrac{t^2}{a}.

8 0
3 years ago
Finding the distance between the points (−3,−2)<br> and (7,4)
ycow [4]

Answer:

11.661904

plz mark me as brainliest.

8 0
2 years ago
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