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2 years ago

Solve this system of equations 5x + 4y = 6 10x -2y = 7

Mathematics

1 answer:

Akimi4 [234]2 years ago

8 0

Answer:

x = 4/5

y = 1/2

Step-by-step explanation:

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Solve for x:1/2(x-2)+1/3(x-3)+1/4(x-4)

Archy [21]

Answer:

$\frac{1}{12} \times (13x - 36)$

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2 years ago

Quadrilateral PQRS is transformed to create quadrilateral P’Q’R’S

oee [108]

Answer:

Step-by-step explanation:

Reflection over the X-axis

All point passes, (x,-y)

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1 year ago

Read 2 more answers

What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

zheka24 [161]

Answer:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

Step-by-step explanation:

Given

$A = (1,1)$ $B =(2,3)$

$C = (4,3)$ $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

$C = (4,3)$ $=> C' = (-4,3)$ $=> C" =(-4,1)$

$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

5 0

2 years ago

Suppose that 71% of the surface of the Earth is covered in water, and a random number generator uses latitude and longitude to s

erik [133]

Answer:

.00059 or .0006

Step-by-step explanation:

You are trying to find what won't be in the water because there are many combinations so you use a complement formula.

1-0.79=0.29

Use the left over percentage in an equation to determine the probability.

$1-(0.29)^6=0.000594823$

The exponent 6 comes from the number of locations.

8 0

2 years ago

Given that GK is a perpendicular bisector to JH which two triangles are congruent by the HL theorem

Digiron [165]

JGK is congruent to HGK

3 0

3 years ago