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3 years ago

10

Community Gym charges a $60 membership fee and a $60 monthly fee. Workout Gym charges a $200 membership fee and a $50 monthly fe

e. After how many months will the total amount of money paid to both gyms be the same? What will the amount be?

1 answer:

Kitty [74]3 years ago

8 0

Answer:

14 months

Step-by-step explanation:

60x+60=50x+200

10x+60=200

10x=140

x=14

60(14)+60=900

50(14)+200=900

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You practice your basketball shots every day. On Friday you made 20 shots. On Saturday you made 16 shots. What is the percent de

STatiana [176]

So,

All you have to do to find the percent decrease is to subtract your score on Saturday from your score on Friday and divide the result by your score on Friday. If you let "f" represent your score on Friday and let "s" represent your score on Saturday, you can re-write this mathematically:

$\frac{f - s}{f} = percent\ decrease$

Substitute.
$\frac{20 - 16}{20} = percent\ decrease$
$\frac{4}{20} \ or\ \frac{1}{5}\ or\ twenty\ percent = percent\ decrease$

The percent decrease in shots you made was 20%. That would be option C.

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3 years ago

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1.5 cups per day how many gallons per weeek? (1gallon =16cup)

anyanavicka [17]

So as you know, one gallon has 16 cups, and there's 7 days in a week. So, if you multiple 1.5 by 7 you would get 10.5 cups per week, then divide that by 16 and get .65625 gallons per week.

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3 years ago

An observer at the top of a 532 foot cliff measures the angle of depression from the top of the cliff to a point on the ground t

Over [174]

Answer:

Distance from the base of the cliff to the point on the ground = 7608 feet

Step-by-step explanation:

Given: Height of the cliff is 532 feet, angle of depression from the top of the cliff to a point on the ground is equal to 4 degrees.

To find: distance from the base of the cliff to the point on the ground

Solution:

In ΔABC,

$\angle ACB=4^{\circ}$ (Alternate interior angles)

For any angle $\theta$ , $\tan \theta =$ side opposite to angle/side adjacent to angle

$\tan C=\frac{AB}{BC}$

Put $AB=532\,,\,\angle C=4^{\circ}$

$\tan 4^{\circ}=\frac{532}{BC}\\\\BC=\frac{532}{\tan 4^{\circ}}\\\\=7607.95\\\\\approx 7608\,\,feet$

Distance from the base of the cliff to the point on the ground = 7608 feet

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3 years ago

What 5+5=10 5+23#qrka

jolli1 [7]

5+23= 28 .........................

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Joanna went to the farmers market to buy some apples and oranges. She bought 8 oranges and some apples. The cost per orange was

MArishka [77]

Joanna would have spent $8.94 on apples at the farmers market.

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