What is a million times all the numbers in the world

1 answer:

7 0

Well, there isn’t really an end for numbers...

However; The biggest number referred to regularly is a googolplex (10googol), which works out as 1010^100. That isn’t the end to numbers but it is a huge one. We will replace that with ‘all the numbers in the world’.

106 is the exponent equivalent to 1 million

So your question would be:
106 x 1010^100 =

However I don’t believe there is a calculator that large.

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What is the expression for the below sequence (use n)<br><br> -3,-6,-9,-12

polet [3.4K]

Answer:

$a_{n}$ = - 3n

Step-by-step explanation:

There is a common difference between consecutive terms, that is

- 6 - (- 3) = - 9 - (- 6) = - 12 - (- 9) = - 3

This indicate the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3 and d = - 3 , thus

$a_{n}$ = - 3 - 3(n - 1) = - 3 - 3n + 3 = - 3n

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A figure is shown with the given dimensions. What is the area of the composite figure?

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Answer:

Step-by-step explanation:

Split the shape into 2 so you get a triangle and a rectangle.

Find area of triangle:

1/2 x a x b = 1/2 x 3 x 4

= 6 square feet

Find area of rectangle:

b x h = 6 x 3

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3 years ago

PLEASE HELP!<br>Calculate $40^{13} \pmod{85}.$

SVEN [57.7K]

In this type of calculations, we decompose 13 by checking the lowest powers of the base, that is 40. for example we check 40^2, or 40^3 and compare it to 85

Notice

40*40*40=64,000

so we check how many time does 85 fit into 64,000:

64,000/85=752.94

85*753=64,005; 64000-64,005=-5

this means that

$40^{3} =-5\pmod{85}$

thus

$40^{13} =40^{3*4+1}={(40^{3})}^{4}*40=(-5)^{4}*40 \pmod{85}=\\\\625*40\pmod{85}=(7*85+30)*40\pmod{85}=30*40\pmod{85}\\\\=1200\pmod{85}=(14*85+10)\pmod{85}=10\pmod{85}$

Answer: 10 (mod85)

Remark, the set of all solutions is:

{......-75, 10, 95, .....}, that is 85k +10

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I dont understand you already answered

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