Answer: ![\dfrac{3}{51}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B51%7D)
Step-by-step explanation:
![\text{Probability of any event}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20of%20any%20event%7D%3D%5Cdfrac%7B%5Ctext%7BFavorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D)
Given : The number of cards in a standard deck of cards = 52
The number of jack in a deck of cards = 4
The probability of drawing the first card as jack :-
![\dfrac{4}{52}=\dfrac{1}{13}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B52%7D%3D%5Cdfrac%7B1%7D%7B13%7D)
If there is no replacement , the the total number of cards left = 51
The number of jack is left = 3
Then , the probability of choosing a jack for the second card drawn :-
![\dfrac{3}{51}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B51%7D)
Answer:
78
Step-by-step explanation:
Since 13 is a prime, the least common multiple of it and 6 is their product. 6*13=78. Hope this helps!
Answer:
3n + 3
Step-by-step explanation:
Mia is correct
When n= 1 , 3n + 3 = 3*1 + 3 = 3 + 3 = 6
When n =2, 3n + 3 = 3*2 + 3 = 6 + 3 = 9
When n = 3 , 3n +3 = 3*3 + 3 = 9 + 3 = 12
When n = 4, 3n + 3 = 3*4 + 3 = 12 +3 = 15
Answer:
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