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Virty [35]
2 years ago
5

H(n) = 3^n+3; Find h (3n)

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
5 0

Answer:

The option which you chose is absolutely right.

Step-by-step explanation:

h(n) = 3^ n + 3

h(3n) = 3 ^3n + 3

Hope it will help :)

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Write a quadratic function whose graph has a vertex of (3,2) and passes through the point (4,7). f(x)=
agasfer [191]

Answer:

y=5(x-3)^2+2

Step-by-step explanation:

You plug the point into f(x)=a(x-3)^2+2... that already has already been solved for the vertex that you want. Then you swap it out for the solution you have solved for.

7 0
2 years ago
Y = 5x - 22 y = 4x - 17
Pie
The answer is (5,3). You need to equal both sides out. So 5x-22=4x-17. That will give you x=5. After that you substitute 5 for x in one or both of the equations and get that y=3. Hope this helps!
6 0
2 years ago
Read 2 more answers
Please help on the area for 7 8 9 please all i need help is
weeeeeb [17]

The area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

<h3>What is the area of the equilateral, isosceles and right angle triangle?</h3>

Note that:

The area of an Equilateral triangle is expressed as A = ((√3)/4)a²

Where a is the dimension of the side.

The area of an Isosceles triangle is expressed as A = (ah)/2

Where a is the dimension of the base and h is the height.

The area of a Right angled triangle is expressed as A = (ab)/2

Where a and b is the dimension of the two sides other than the hypotenuse.

For the Equilateral triangle.

Given that;

  • a = 5.4mm
  • Area A = ?

A = ((√3)/4)(5.4mm)²

A = ((√3)/4)( 29.16mm² )

A = 12.6mm²

Area of the Equilateral triangle is 12.6mm²

For the Isosceles triangle.

Given that;

  • Base a = 3.4in
  • Slant height b = 5.9in
  • height h = ?
  • Area A = ?

The height h is the imaginary line drawn upward from the center of a.

First, we calculate the height using Pythagorean theorem

x² = y² + z²

Where x = b = 5.9in, y = a/2 = 3.4in/2 = 1.7in, and z = h

(5.9in)² = (1.7in)² + h²

34.81in² = 2.89in² + h²

h² = 34.81in² - 2.89in²

h² = 31.92in²

h = √31.92in²

h = 5.65in

Now, the area will be;

A = (ah)/2

A = (3.4in × 5.65in )/2

A = 19.21in²/2

A = 9.61in²

Area of the Isosceles triangle is 9.61in².

For the Right angled triangle

Given that;

  • a = 8.2yds
  • b = 4.1yds
  • c = 9.17yds
  • Area A = ?

A = (ab)/2

A = ( 8.2yds × 4.1yds)/2

A = ( 33.62yds²)/2

A = 16.81yds²

Area of the Right angled triangle is 16.81yds²

Therefore, the area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

Learn more about Pythagorean theorem here: brainly.com/question/343682

#SPJ1

6 0
1 year ago
1) Find the slope.<br><br>2) write an equation​
hodyreva [135]

Answer:

Well, 10

Step-by-step explanation:

Because I am SMART

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2 years ago
Select all the numbers that show 4% as an equivalent fraction, decimal, or percent.
max2010maxim [7]

Answer:

Step-by-step explanation:

0.04

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2 years ago
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