V = 1¹/₃πr³
V = 1¹/₃(3.14)(2)³
V = 1¹/₃(3.14)(8)
V = 1¹/₃(25.12)
V ≈ 33.493 in³
Y = 4 x - 9
y = - 3 x - 5
I hope this will help you
i looked this up and this is what i got
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
Answer: 242 = 190 + 4t
Step-by-step explanation:
You know that the maximum capacity of the restaurant is 242 people, meaning that at most there can only be that many customers seated at that time. Normally, the equation would be 242 = 10b + 4t, but since you already know the number of booths, your work is cut in half, giving you 242 = 10(19) + 4t. The equation would be this because you have the capacity being equal to the number of tables x the number of people at each table and the number of booths x the number of people seated at each of them.
