All categories

1 year ago

(Giving 80 points, Please do not answer if you don't know. The second and third answer are not 4 btw)

Mathematics

2 answers:

garik1379 [7]1 year ago

7 0

Answer:

1. BC = 4

2. AC = 10

3. AD = 14

Step-by-step explanation:

Ruler Postulate

The distance between any two points on a number line is their difference.

Question 1

Given:

Point B = 0
Point C = 4

Therefore, using the Ruler Postulate:

⇒ BC = |b - c|

⇒ BC = |0 - 4|

⇒ BC = |-4|

⇒ BC = 4

Question 2

Given:

Point A = -6
Point C = 4

Therefore, using the Ruler Postulate:

⇒ AC = |a - c|

⇒ AC = |-6 - 4|

⇒ AC = |-10|

⇒ AC = 10

Question 3

Given:

Point A = -6
Point D = 8

Therefore, using the Ruler Postulate:

⇒ AD = |a - d|

⇒ AD = |-6 - 8|

⇒ AD = |-14|

⇒ AD = 14

Jobisdone [24]1 year ago

3 0

Answer:

1. 4

2. 10

3. 14

Step-by-step explanation:

A = -6

B = 0

C = 4

D = 8

1. BC = |0 - 4| = 4

2. AC = |-6 - 4| = |-10| = 10

3. AD = |-6 - 8| = |-14| = 14

You might be interested in

Which of the following expressions is equivalent to the radical expression?

qwelly [4]

The correct answer is B) $m^{2/3}n^{5/3}$ .

The denominator of the exponent is the root we are taking. The numerator is the exponent of the radicand. This means 3 will be the denominator, since it is a cubed root, and 2 will be the numerator of m while 5 will be the numerator of n.

4 0

3 years ago

You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5 1/6 minutes to set up the

igomit [66]

Answer:

Step-by-step explanation:

Given,

The time for set up the game = $5\frac{1}{6}$ minutes,

Also, the time for each level of game is $7\frac{1}{3\\}$ minutes,

If there are l levels of games,

Then the time taken in all levels of game = $(7\frac{1}{3}) l$

Hence, the total time ( in minutes ) = Set up time + time in all level

= $5\frac{1}{6} +(7\frac{1}{3}) l$

We have 60-minute of free trial of the game,

So, the total time taken can not be exceed to 60 minutes,

= $5\frac{1}{6} +(7\frac{1}{3}) l\leq 60$

Which is the required inequality.

Option 'B' is correct.

5 0

2 years ago

72÷8+3.4-105÷5 they say the answer is 0 but don't see how.

Sidana [21]

72/8 +3*4 - 105 /5
= 9 + 12 - 21
= 21 -21
= 0

4 0

2 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Describe the end behavior of the given function f(x)=9x^3-x^2-8x+6

Mekhanik [1.2K]

As x approaches -inf f(x) -> -inf
and as x approaches inf, f(x) approaches +inf

Mark brainliest please

6 0

2 years ago