Point U is on line segment TV. Given UV = 4 and TU = 13, determine the length TV.
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The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
Learn more on midpoint of a line here: brainly.com/question/5566419
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<h2>Answer:</h2>
0 - 17i
<h2>Step-by-step explanation:</h2>Given expression;
i⁸⁰ + i³⁸ - i17
To express the expression in the form a+bi;
<em>i. Rewrite the expression such that it contains terms in i²</em>
(i²)⁴⁰ + (i²)¹⁹ - i17
<em>ii. Solve the result from (i) above using the identity i² = -1</em>
We know that the square root of -1 is i. i.e
<em>Squaring both sides gives</em>
<em>=> </em><em />
=> -1 = i²
Therefore,
i² = -1
<em>Substitute i² = -1 in step (i) above</em>
(-1)⁴⁰ + (-1)¹⁹ - i17
<em>(iii) Solve the result in (ii)</em>
We know that the when a negative number is raised to the power of an even number, the result is a positive number. If it is raised to the power of an odd number, the result is a negative number. Therefore,
(-1)⁴⁰ + (-1)¹⁹ - i17 becomes
1 + (-1) - i17
0 - i17
<em>(iv) Write the result from (iii) in the form a+bi</em>
0 - 17i