The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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Answer:
324
Step-by-step explanation:
Simplify it
√52-√13+√117
sqrt (4*13) - sqrt (13) + sqrt (13*9)
sqrt(4)sqrt(13) -sqrt(13)+sqrt(13)sqrt(9)
2sqrt(13) -sqrt(13)+3sqt(13)
sqrt(13)[2-1+3]
4sqrt(13)
Choice A