a. Based on the AA similarity theorem, Gilligan can conclude that, ΔABC ~ ΔSDC.
b. To the nearest tenth of a foot, the distance from the ship to the shore is: 847.8 ft.
<h3>What are Similar Triangles?</h3>
The ratios of the corresponding sides of two triangles that are similar are equal.
Two triangles with two pairs of congruent angles are similar to each other based on the AA similarity theorem.
a. In ΔABC and ΔSDC, there are two pairs of congruent angles - ∠DCS ≅ ∠BCA (vertical angles) and ∠ABC ≅ ∠SDC (right angles)
Therefore, based on the AA similarity theorem, Gilligan can conclude that, ΔABC ~ ΔSDC.
b. AB = 150 ft
Distance from the ship to the shore = SD = ?
DC = 130 ft
CB = 23 ft
Thus:
AB/SD = CB/DC
Substitute
150/SD = 23/130
SD = (150×130)/23
SD = 847.8
Thus, to the nearest tenth of a foot, the distance from the ship to the shore is: 847.8 ft.
Learn more about similar triangles on:
brainly.com/question/11899908
Answer:
x=90 degrees
Step-by-step explanation:
It is a right corner. Please give branliest
Answer:
The mean for the second week is $2 less than the first and in percentage it is 22% less.
Step-by-step explanation:
The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:
sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75
sum1 = 45
Since she spent 10 less in the second week the sum is:
sum2 = sum1 - 10 = 45 - 10 = 35
The mean for each week is:
mean1 = sum1/5 = 45/5 = 9
mean2 = sum2/5 = 35/5 = 7
difference = mean1 - mean2 = 9-7 = 2
difference(%) = [2/9]*100 = 0.22*100 = 22%
The mean for the second week is $2 less than the first and in percentage it is 22% less.
The pattern is count by 2
