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kotegsom [21]
3 years ago
11

I need help on this, please hurry and thank you!

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer: A.

<u>Step-by-step explanation:</u>

2, 5, 10, 17, 26

First, check the difference between each term:

2 → 5 = +3

5 → 10 = +5

10 → 17 = +7

17 → 26 = +9

Since the difference (d) is not the same, this is not an arithmetic sequence.

Now, check the second tier {3, 5, 7, 9}

3 → 5 = 2

5 → 7 = 2

7 → 9 = 2

The difference (d) of the second tier is the same, so it is an exponential sequence.

--> the only option that is an exponential sequence is option A.

inna [77]3 years ago
4 0

Answer:

A.\ a_n=n^2+1

Step-by-step explanation:

Check:

a_n=n^2+1\\\\a_1=1^2+1=1+1=2\qquad CORRECT\\\\a_2=2^2+1=4+1=5\qquad CORRECT\\\\a_3=3^2+1=9+1=10\qquad CORRECT\\\\a_4=4^2+1=16+1=17\qquad CORRECT\\\\a_5=5^2+1=25+1=26\qquad CORRECT

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

First Power, next Addition

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Solve 3.8 = p/3 - 7.2
ziro4ka [17]
19/5=p/3-36/5

Convert the decimals into fractions

15 x 19/5=(p/3-36/5) x 15

Multiply both sides by 15

57=5x-108

5x-108+108=57+108

Add 108 to both sides

5x=165

X=33

Answer

Hope this helps
7 0
3 years ago
Can some explain how to do this?
zepelin [54]

Answer:

  • Exact Area = 210.25pi - 210
  • Approximate Area = 450.185

The units for the area are in square inches or in^2. The approximate value shown above is when using pi = 3.14

=============================================================

Explanation:

Use the pythagorean theorem to find the length of the hypotenuse

  • a = 20
  • b = 21
  • c = unknown

a^2 + b^2 = c^2

20^2 + 21^2 = c^2

400 + 441 = c^2

c^2 = 841

c = sqrt(841)

c = 29

The hypotenuse is 29 inches long. This is the diameter of the circle. Half of that is the radius at r = d/2 = 29/2 = 14.5 inches.

The area of the circle is...

A = pi*r^2

A = pi*(14.5)^2

A = pi*210.25

A = 210.25pi

Which is exact in terms of pi

We'll subtract off the triangular region as this isn't shaded in. The area of the triangle is base*height/2 = 20*21/2 = 420/2 = 210 square inches.

So the shaded region is therefore 210.25pi - 210 square inches

This approximates to 210.25*3.14 - 210 = 450.185 when using the approximation pi = 3.14; use more decimal digits of pi to get a more accurate value.

4 0
3 years ago
7x − 5 &lt; 13x − 3 <br><br>PLz anyone
Ksju [112]

7x-5<13x-3

Minus 7x

-5<6x-3

then add 3

-2<6x

Then divide -2 by 6 and 6x by 6

-1/3>x

I think thats right

4 0
3 years ago
5milimeter7centimeter+1milimiter=
Marrrta [24]
7milimeters7centumeters
8 0
3 years ago
the total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib. if the weight of the bag of sugar is 1.4 Ib, what is the we
baherus [9]

0.4 lbs each.

<h3>Further explanation</h3>

<u>Given: </u>

  • The total weight of 6 pieces of butter and a bag of sugar is 3.8 Ib.
  • The weight of the bag of sugar is 1.4 Ib

<u>Question: </u>

What is the weight of each piece of butter?

<u>The Process: </u>

The two steps for obtaining the weight of each piece of butter are as follows:

<u>Step-1:</u> the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

\boxed{ \ 3.8 \ lbs - 1.4 \ lbs = 2.4 \ lbs \ }

<u>Step-2:</u> the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

\boxed{ \ 2.4 \ lbs \div 6 \ pieces = \boxed{ \ 0.4 \ lbs/piece \ } \ }

Let's also consider the following quick steps.

<u>Quick steps: </u>

\boxed{ \ \frac{(3.8 - 1.4) \ lbs}{6 \ pieces} = \boxed{ \ 0.4 \ lbs/piece \ } \ }

Therefore, the weight of each piece of butter is 0.4 lbs.

<h3>Learn more </h3>
  1. What is the cost of the toy car? brainly.com/question/5282516
  2. How much netting did Mrs.Nguyen use per goal? brainly.com/question/13174287    
  3. How much punch is in each bowl? brainly.com/question/1878521

Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

5 0
3 years ago
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