(21/25) * 100
84 %
82 %
0.8 * 100
80 %
(17/20) * 100
85 %
17/20 is the highest one
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
-1
Step-by-step explanation:
x - 1x - 1
1x = x
x - x -1
x - x = 0
0 - 1 = -1
-1
Answer:
Step-by-step explanation:
The volume of a rectanguiar shape like this one is V = L * W * H, where the letters represent Length, Width and Height. Here L is the longest dimension and is 28 - 2x; W is the width and is 22-2x; and finally, x is the height. Thus, the volume of this box must be
V(x) = (28 - 2x)*(22 - 2x)*x
and we want to maximize V(x).
One way of doing that is to graph V(x) and look for any local maximum of the graph. We'd want to determine the value of x for which V(x) is a maximum.
Another way, for those who know some calculus, is to use the first and second derivatives to identify the value of x at which V is at a maximum.
I have provided the function that you requested. If you'd like for us to go all the way to a solution, please repost your question.
Answer:
x ≈ 14.30
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Trigonometry</u>
- sin∅ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Define variables</u>
∅ = 39°
opposite leg = 9
hypotenuse = x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute: sin39° = 9/x
- Multiply <em>x</em> on both sides: xsin39° = 9
- Isolate <em>x</em>: x = 9/sin39°
- Evaluate: x = 14.3011
- Round: x ≈ 14.30