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marissa [1.9K]
3 years ago
15

Please show me step by step on how to solve this.

Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0
Well, you have to be given an interval. That is not an interval.

You should be given something like 1 \leq x \leq 2

If you add those fractions up you'll just get a point on the number line.

Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3

You'll end up with a point on 2/3 
You might be interested in
Question 16
Artyom0805 [142]

Answer:

16

Step-by-step explanation:

5 + 9 \div 3 + 4  \times  2 \\  = 5 + 3 + 8 \\  = 16

Multiplication and division are priority to addition and subtraction

Brainliest please

7 0
3 years ago
Given ΔKLM with lengths as marked, what is the relationship of segment NO to segment KL?
Oliga [24]

Segment NO is parallel to the segment KL.

Solution:

Given KLM is a triangle.

MN = NK and MO = OL

It clearly shows that NO is the mid-segment of ΔKLM.

By mid-segment theorem,

<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>

⇒ NO || KL and NO = \frac{1}{2}KL

Therefore segment NO is parallel to the segment KL.

6 0
3 years ago
The wildflowers at a national park have been decreasing in numbers. There were 1200 wildflowers in the first year that the park
Andreas93 [3]

Answer:

Step-by-step explanation:

We have total 1200 wildflowers in first year that is first term a  is 1200

We have to find sigma notation  showing the infinite growth of the wildflowers.

wildflowers=\sum_{i=1}^{\infty }1200(\frac{1}{4})^{i-1}

Formula for infinite sum of GP is S_{\infty}=\frac{a}{1-r}

Here, a=1200,r=\frac{1}{4}

On substituting the values in the formula of sum we get:

S_{\infty}=\frac{1200}{1-\frac{1}{4}}

On simplification we get:

S_{\infty}=\frac{1200}{\frac{3}{4}}=1600

Therefore, total sum of wildflowers 1600.

5 0
3 years ago
Read 2 more answers
M is the midpoint of AB.<br> AM = = 4x - 8<br> MB =<br> 5x-3/3<br> Find x and AB
marusya05 [52]
X=-7 AB=-72

steps

since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7

then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72
7 0
3 years ago
Can someone help me?
Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A =  { a^2  -  4  = 0 }

A = { a^2  = 0+ 4 }

A = { a^2  = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= (  { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 }  ∩  { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0
3 years ago
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