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Serga [27]
2 years ago
8

Given the function f(x)= 3(x-2)² + 5, what is f(-1)?

Mathematics
2 answers:
motikmotik2 years ago
5 0

Answer:

32

Step-by-step explanation:

f(x)= 3(x-2)² + 5

Let x = -1

f(-1)= 3(-1-2)² + 5

Parentheses first

f(-1) = 3(-3)^2 +5

Exponents

f(-1)= 3*9 + 5

Multiply

f(-1) = 27+5

Add

f(-1) = 32

Anna11 [10]2 years ago
5 0
Answer: 32

=3(-1-2)^2+5
=3(-3)^2+5
=3•3^2+5
=3^3+5
=27+5
=32

Explanation: Plug in -1 for x in the function and solve.
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