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Serga [27]
3 years ago
8

Given the function f(x)= 3(x-2)² + 5, what is f(-1)?

Mathematics
2 answers:
motikmotik3 years ago
5 0

Answer:

32

Step-by-step explanation:

f(x)= 3(x-2)² + 5

Let x = -1

f(-1)= 3(-1-2)² + 5

Parentheses first

f(-1) = 3(-3)^2 +5

Exponents

f(-1)= 3*9 + 5

Multiply

f(-1) = 27+5

Add

f(-1) = 32

Anna11 [10]3 years ago
5 0
Answer: 32

=3(-1-2)^2+5
=3(-3)^2+5
=3•3^2+5
=3^3+5
=27+5
=32

Explanation: Plug in -1 for x in the function and solve.
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Need help solving algebraically!
alekssr [168]
We need to account for both x values on either side of the length, and width.
Thus, the length becomes 10 + x + x = 10 + 2x
and the width becomes 5 + x + x = 5 + 2x

For the second question, I'm assuming we don't account for the area that is covered by the garden.
Then we can say that the path is measured by: (5 + 2x)(10 + 2x) - 50, which is the area of the garden itself.

(5 + 2x)(10 + 2x) - 50 = 54

Expanding the brackets:
50 + 10x + 20x + 4x^{2} - 50 = 54
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x(2x - 3) + 9(2x - 3) = 0

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6 0
3 years ago
The recursive rule for a sequence is shown.an=an−1+9a1=21 what is the explicit rule for this sequence?
bixtya [17]

Answer:

Meaning of Explicit rule , is the general rule for a sequence.

The given sequence is defined as,

a_{n}=a_{n-1}+9a_{1}-21----(1)

Common Difference(d) of an airthmetic Sequence= N th term - (N-1) th term

                                 =a_{n}-a_{n-1}\\\\=a_{n-1}-a_{n-2}                                            

Equation 1 can be written as,

a_{n}-a_{n-1}=9 a_{1}-21\\\\ d =9a_{1}-21

General rule or explicit rule for this sequence is given as:

a_{n}=a_{1} +(n-1)d\\\\a_{n}=a_{1}+(n-1)(9a_{1}-21)\\\\a_{n}=a_{1}+9na_{1}-21 n-9a_{1}+21\\\\a_{n}=-8a_{1}+21+n(9a_{1}-21)

6 0
3 years ago
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timofeeve [1]

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