(c) Simplify fully exexexf ———— exex fxf
2 answers:
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Answer:
(-3, 5), (-1, -1), (5, -3)
Step-by-step explanation:
Each pair of vertices can be one of the diagonals. Then the missing point will be found at the coordinates that are the sum of those, less the coordinates of the third point.
Given points are ...
A(-2, 2), B(1, 1), C(2, -2)
For AB a diagonal, D1 is ...
A+B-C = (-2+1-2, 2+1-(-2)) = (-3, 5)
For AC a diagonal, D2 is ...
A+C-B = (-2+2-1, 2-2-1) = (-1, -1)
For BC a diagonal, D3 is ...
B+C-A = (1+2-(-2), 1-2-2) = (5, -3)
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For a lot of parallelogram problems I find it easiest to work with the fact that the diagonals bisect each other. This means they both have the same midpoint, so for quadrilateral ABCD, we have (A+C)/2 = (B+D)/2. Multiplying this by 2 gives the equation we used above, A+C = B+D, so D=A+C-B. Remember, in ABCD, AC and BD are the diagonals.
We will be using the Point Slope formula which is
The information we are given is that m = -4 and the point is (2,-5), so we can input it into the equation.
This simplifies into
Then we can subtract 5 from each side to get the answer: