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aleksley [76]
2 years ago
10

PLEASE HELP!!!

Mathematics
1 answer:
Klio2033 [76]2 years ago
6 0

Answer:

The answer is A and B

Step-by-step explanation:

y-y=m(x-x)

y-(-3)=m(x-(-5))

y+3=0.4(x+5)

y-y=m(x-x)

y-1=0.4(x-5)

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If 12 key chains cost $35.35, what is the cost of 20 key chains
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Answer:

The key chain's are 0.75 each

Step-by-step explanation:

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2 years ago
What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?
Masteriza [31]

Answer:c

Just had it on apex


Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
Help me please :/ ill mark you braniest also please show ur work
Nimfa-mama [501]

Answer:

Surface area = 2 (lw + lh + wh)

= 2 [(5*4) + (5*7) + (7*4)]

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5 0
2 years ago
Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
a fundraiser raised $2400 , which was 3/5 of the goal . write an equation and solve it to find the goal
GuDViN [60]

First of all, 2400=0.6x is the equation

Now, we use cross multiplication

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