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ivanzaharov [21]
3 years ago
11

Please help me I’ve been stuck for awhile

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Hey there! I'm happy to help you out!

Let's think of our original price ($P) as 100%. This is also the same thing as 1 because 100% is one whole thing.

Now, we see that he got a 15% off discount. Now, we just subtract 15% from 100% to see what percent he actually payed.

100%-15%=85%

This means that $R is 85% of $P (100%).

Answer A is not correct because 0.85% is less than 1%, which is not 85%.

Answer B is not correct either because 0.15% is also less than 1%.

Answer C is correct because $R is 85% of the original cost.

I hope that this helps! Have a wonderful day!

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Answer:

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The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

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E = \frac{n}{p} = \frac{1}{0.02} = 50

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V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

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