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NISA [10]
3 years ago
10

For what value of x is the rational expression below when x is equal to 4? X+20/x+4

Mathematics
2 answers:
Olenka [21]3 years ago
8 0

It would be 24  4×20/4+4 80/4 20+4 24

Zanzabum3 years ago
4 0

Answer:

the answer is 3

Step-by-step explanation:

apex said so <3

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Find the Area of the figure below, composed of a rectangle and a semicircle. The
IRISSAK [1]

Answer:

What grade math is this??

Step-by-step explanation:

4 0
3 years ago
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What is The simple interest earned on a deposit of $3000 at 6% for five years
Norma-Jean [14]

Answer: $900

Step-by-step explanation:

The simple interest is calculated using the formula:

(P × R × T)/100

where,

P = Principal = $3000

R = Rate = 6%

T = Time = 5 years

Simple Interest = (P × R × T)/100

= ($3000 × 6 × 5)/100

= 90000/100

= $900

Therefore, the simple interest is $900

4 0
3 years ago
Suppose that on your college campus building a is east of building b, but they aren't exactly in a straight row; one is 15 feet
Neporo4naja [7]

Answer:

Alignment Heuristic parameters.

Step-by-step explanation:

The students' cognitive maps shows them in a straight row because the students have used "Alignment Heuristic" parameters.

4 0
3 years ago
A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
Kitty [74]

Answer:

It does not appear ​that, as a​ group, the students are reasonably good at estimating one minute.

Step-by-step explanation:

We are given the following data in the question:

75, 88, 51, 73, 49, 31, 69, 74, 72, 59, 72, 81, 99, 101, 73

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1067}{15} = 71.13

Sum of squares of differences = 4739.733

S.D = \sqrt{\frac{4739.733}{14}} = 18.39

Population mean, μ = 60 minutes

Sample mean, \bar{x} = 71.13 minutes

Sample size, n = 15

Alpha, α = 0.10

Sample standard deviation, s = 18.39 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 60\text{ minutes}\\H_A: \mu \neq 60\text{ minutes}

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{71.13 - 60}{\frac{18.39}{\sqrt{15}} } = 2.34

Calculating the p-value from the table, we have,

P-value = 0.034354

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, we conclude that it does not appear ​that, as a​ group, the students are reasonably good at estimating one minute.

7 0
3 years ago
How do you solve 9x+2=8x+9
avanturin [10]
Try solving for the variable and get everything to one side
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