Question

Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bag_ounces followed by "seconds". End with a newline.

Answer 1

Answer:

void print_popcorn_time(int bag_ounces){

   if(bag_ounces < 3){

       cout<<"Too small"<<endl;

   }else if(bag_ounces > 10){

       cout<<"Too large"<<endl;

   }else{

       cout<<(6 * bag_ounces)<<"seconds"<<endl;

   }

}

Explanation:

The function is the block of the statement which performs the special task.

For checking the condition in the program, the if-else statement is used.

It can check the condition one or two but if we want to check the more than two different conditions then the continuous if-else statement is used.

syntax of continuous if else:

if(condition){

statement;

}else if(condition)

statement;

}else{

statement;

}

In the question, there are three conditions;

1. bag_ounces is less than 3

2. bag_ounces greater than 10

3. else part.

we put the condition in the above if-else statement and print the corresponding message.

Answer 2

Answer:

def print_popcorn_time(bag_ounces):

   if bag_ounces < 3:

       print("Too small")

   elif bag_ounces > 10:

        print("Too large")

   else:

        bag_ounces = bag_ounces * 6

        print(bag_ounces, "seconds")

Explanation:

def print_popcorn_time(bag_ounces): #fed function

   if bag_ounces < 3:  #1st if statement

       print("Too small") #print function

   elif bag_ounces > 10: #else if

        print("Too large") #print than print

   else:  #else:

        bag_ounces = bag_ounces * 6 #do work

        print(bag_ounces, "seconds") #print