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Dmitry [639]
3 years ago
10

c++ 2.30 LAB: Phone number breakdown Given a long long integer representing a 10-digit phone number, output the area code, prefi

x, and line number, separated by hyphens. Ex: If the input is: 8005551212 the output is: 800-555-1212 Hint: Use % to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 is gotten by 572 % 100, which is 72. Hint: Use / to shift right by the desired amount. Ex: Shifting 572 right by 2 digits is done by 572 / 100, which yields 5. (Recall integer division discards the fraction). For simplicity, assume any part starts with a non-zero digit. So 999-011-9999 is not allowed. LAB
Computers and Technology
1 answer:
Nady [450]3 years ago
5 0

Answer:

#include <iostream>

using namespace std;

int main()

{

   //declare variable to store phone numbers,its area code, prefix and line number.

   long phone_number;

   int area_code, prefix,line_number;

   cout<<"Enter 10-digit phone number:"<<endl;

   //input 10-digit phone number

   cin>>phone_number;

   //logic to find area_code, prefix, and line_number.

   area_code = phone_number/10000000;

   prefix = (phone_number/10000)%1000;

   line_number = phone_number%10000;

   //output phone number in asked format.

   cout<<area_code<<"-"<<prefix<<"-"<<line_number<<endl;

   return 0;

}

Output:

Enter 10-digit phone number:

8005551212

800-555-1212

Explanation:

In the above program 10 digit phone number entered by user will be stored in the variable phone_number.

Then using this phone_number variable area_code, prefix, and line number are calculated using the following logic:

area_code = phone_number/10000000;

prefix = (phone_number/10000)%1000;

line_number = phone_number%10000;

Finally these area_code, prefix, and line_number are displayed with hyphen in between using cout statement.

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Answer:

Explanation:

1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.  

  double alpha[50];

   for (int i=0;i<25;i++)

   {

       alpha[i]=i*i;

       alpha[i+25]=(i+25)*3;

  }

2. Output the array so that exactly ten elements per line are printed.  

   for (int i=0;i<50;i++)

   {

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       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.  

   double alpha[50];

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

   }

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   {

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       {

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   }

4. Write the code that computes and prints the average of elements of the array.  

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

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   }

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5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.

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   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       if(alpha[i]==100)

       {

           temp++;

       }

   }

   cout<<"Elements Exacctly 100 :"<<temp;

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#include <iostream>

using namespace std;

int main()

{

   // If you put  each of above code here it will run perfectly after compiling

   return 0;

}

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