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leonid [27]
2 years ago
10

What is an advantage of using a dynamic hard drive in a vm?

Computers and Technology
1 answer:
Nikolay [14]2 years ago
7 0

The advantage of using a dynamic hard drive in a vm is that the space on the physical computer hard drive us used only when it's needed.

<h3>What is a virtual machine?</h3>

It should be noted that a virtual machine simply means a machine that allows one to run an operating system on your desktop.

The advantage of using a dynamic hard drive in a virtual machine is that the space on the physical computer hard drive us used only when it's needed.

Learn more about virtual machine on;

brainly.com/question/19743226

#SPJ12

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Most keyboards today are in a
BlackZzzverrR [31]
Qwerty format I think.
6 0
3 years ago
Write a program that first gets a list of integers from input. The input begins with an integer indicating the number of integer
meriva

Answer:

package b4;

import java.util.Scanner;

public class TresholdValue {

public static void main(String[] args) {

 // Create an object of the Scanner class to allow for user's input

 Scanner input = new Scanner(System.in);

 // Create a prompt to allow users to enter the set of integers

 System.out.println("Please enter the set of integers, each followed by a space : ");

 // Get the first integer from the set of inputs.

 // Parse the input and convert it into an integer

 // by using the Integer.parseInt() method.

 // Store the result in an integer variable.

 int first = Integer.parseInt(input.next());

 // Create an integer array to hold the other numbers (first number excluded).

 // The array should have a length equal in value to the first number in the set.

 // This has been stored in a variable called "first".

 int[] intarray = new int[first];

 // Create a while loop that populate the intarray with the set of numbers

 int i = 0;

 while (input.hasNext() && i < intarray.length) {

  intarray[i] = Integer.parseInt(input.next());

  i++;

 }

 // Get the last value (threshold) from the intarray.

 // The threshold value is the last element in the array.

 int lastvalue = intarray[intarray.length - 1];

 // Create a prompt before displaying the set of values that are less than or

 // equal to the threshold value.

 System.out.println("Values less than or equal to the threshold value (" + lastvalue + ") are : ");

 // Create a loop to cycle through the array.

 // At each cycle, the element is checked if or not it is less than or equal to

 // the threshold value.

 // If it is less than or equal to, the number is printed.

 for (int j = 0; j < intarray.length - 1; j++) {

  if (intarray[j] <= lastvalue) {

   System.out.print(intarray[j] + " ");

  }

 }

 // (Optional) Close the Scanner object to prevent resource leak

 input.close();

}

}

Explanation:

The program has been written in Java. The source code file has been attached to this response. Please download it for better readability. The code contains comments explaining what goes on on each segment of the code.

Hope this helps!

Download java
3 0
3 years ago
Read 2 more answers
Queries are questions true or false?
makkiz [27]
True

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5 0
3 years ago
How many bits can a memory chip with the below configuration support? For full credit, show how you got the answer.
tatiyna

Answer:

Total Memory= 4 KB = 4096 bytes = 32768 bits

Explanation:

<em><u>1. Data lines are 8 From D0 to D7</u></em>

so

Total memory at single address locations is 8 bits.

<em><u>2. Address lines are 12 (A0 to A11)</u></em>

There are 12 address lines but 3 out 12 are for selction of chip or memory bank.

so only 9 pins are there to address the locations on one chip.

Total No. of address locations on single chip = 2^9 = 512 locations

as 1 location is 1 byte so total memory of single chip is 512 bytes.

<u><em>3. Total Memory Bank </em></u>

There are total 3 selection pins for memory bank.

so

Total chips = 2^3 = 8.

<em><u>4. Total Memory </u></em>

Total size of 1 chip = 512 bytes

Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb

<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>

5 0
3 years ago
What should you keep in mind when installing hard drives?
Diano4ka-milaya [45]
Always touch a metal object before installing to prevent short circuiting the hard drive.
5 0
3 years ago
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