Find the mean and median of the data. 12, 15, 16, 18, 20, 90 please help!!!

Hi I need this asap if you also explain the work on how you got answers plz and thank you

weeeeeb [17]

Answer:

Q/ Draw a line ; Ans; 

$\frac{9}{5} —>1 \frac{4}{5}$

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .

Ans; 7/3—> 2 1/3

*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .

Ans; 12/10 —> 1 1/5

*explain; simple (12 and 10) ÷ 2 so equal 6/5

We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

$\frac{12 \div 2}{10 \div 2} = \frac{6}{5} = 1 \frac{1}{5}$

Q/ Compare the fractions;Ans;

$\frac{2}{3} < \frac{14}{6}$

* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .

$\frac{3}{8} < \frac{8}{3}$

* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .

$2 \frac{1}{6} > \frac{5}{9}$

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6

13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .

Q/Add; Ans;

$\frac{7}{8} + \frac{5}{8} = \frac{7 + 5}{8} = \frac{12}{8} = \frac{3}{2}$

$\frac{1}{9} + \frac{2}{3} \\ \\ \frac{1}{9} + \frac{6}{9} = \frac{ 1+6 }{9} = \frac{7}{9}$

Q/Subtract; Ans;

$\frac{6}{7} - \frac{4}{7} = \frac{6 - 4}{7} = \frac{2}{7}$

$\frac{7}{3} - \frac{2}{9} \\ \\ \frac{21}{9} - \frac{2}{9} = \frac{21 - 2}{9} = \frac{19}{9}$

Q/ Multiply;Ans;

$\frac{1}{5} \times \frac{1}{2} = \frac{1}{10}$

$\frac{2}{3} \times \frac{3}{8} = \frac{6}{24} = \frac{1}{4}$

Q/Divide;Ans;

$\frac{3}{4} \div \frac{2}{5} \\ \\ \frac{3}{4} \times \frac{5}{2} = \frac{15}{8}$

$\frac{8}{9} \div \frac{1}{3} \\ \\ \frac{8}{9} \times \frac{3}{1} = \frac{24}{9} = \frac{8}{3}$

I hope I helped you^_^

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