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3 years ago

1) What is the difference between a number and its positive square root is 12. Find the number

Mathematics

1 answer:

hjlf3 years ago

3 0

Answer:

algebra

Step-by-step explanation:

using algebra form an equation than solve for the variable keep in mind u have to square it

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If x=2 and y=5, how would you work out 2y to the power of 2?

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Answer:

Step-by-step explanation:

(5)^

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3 years ago

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The melting point of substance X is -20 degrees Celsius and the boiling point is 90 degrees Celsius. How many Celsius degrees ar

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To find the distance between 2 numbers you must take the absolute value of the difference

|90-(-20)|
|110|
110

110 degrees celsius

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2 years ago

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2/3 * (-3) h SD j ni djndjifnr

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2/3 x (-3)
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2 years ago

In a race , Ram covers 5 km in 20 min. How much distance will he cover in 100 min ?

bulgar [2K]

Answer:

25 km

Step-by-step explanation:

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3 years ago

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

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3 years ago