When a sales manager determines that her staff is not making sufficient progress toward meeting monthly sales quotas and develop
1 answer:
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Answer:
1. Discount
2. $449,298.47
3. $369,298.47 gain
4. land reduces by $80,000, investment increases by $449,298.47, reserves increases by $369,298.47
Explanation:
Question 1
Using the formula below
where
I = interest rate, which is 6% of 500,000 = 30,000
F = Face value, 500,000
r = borrowing cost = 12%
Therefore, the price of the note at the time it was used for payment was
= $449,298.47.
As the price is lower than the face value of the note, the note was issued at a discount.
Question 2
The fair market value of the note is $449,298.47, the compute price in question 1.
Question 3
The gain/loss on the sale of the land
= sale price - purchase price
= $449,298.47 - 80,000
= $369,298.47.
Question 4
The transaction would affect Crabb & Co's balance sheet as follows.
<em>Asset side:</em>
land reduces by $80,000
investment increases by $449,298.47
<em>Equity & liabilities side:</em>
reserves increases by $369,298.47
Answer:
The monthly payment will be = $5161.08
The final payment will be: = $413,684.38
Explanation:
From the given information:
Given that:
the loan amount = $521000
The interest rate for the loan is = 8.6% compounded monthly
the loan is being amortized for 15 years
Thus, the firm will be paying the due amount after 15 years
We use the Excel software to find the monthly payment and the final payment.
a. Using the Excel Function ( =PMT(8.6%/12,15*12,-521000) )
The monthly payment will be = $5161.08
b.Using the Excel Function (=CUMPRINC(8.6%/12,15*12,521000,60,180,1) )
The final payment will be: = $413,684.38
These can be seen in the images attached below.
Answer:
A)Minimum = 0.2 minutes
Maximum = 4.6 minutes
Cycle time = = 2 minutes per unit
B) Number of Stations = 3
D) the percentage of idle time for the assignment in decimal = 0.43
Explanation:
A) Operating output = 240 units per 8hours.
Converting to per hour, we get; 240/8 = 30 units per hour.
Minimum cycle time = longest task time
Maximum cycle time = sum of task times
Minimum = 0.2 minutes
Maximum = 0.2 + 0.4 + 0.2 + 0.4 + 1.2 + 1.2 + 1.0 = 4.6 minutes
Now, operational time(OT) is 8 hours a day. Converting that to minutes, we have =60x8 = 480 minutes
Cycle time(CT) = OT (per day) /desired output
Therefore, calculated cycle time = 480/240
= 2 minutes per unit
B) Number of stations = Maximum time / CT
= 4.6/2 = 2.3 which is approximately 3 stations
C) The task diagram is drawn in image 1 attached. Therefore, we can assign tasks based in the greatest number of following tasks as follows;
Task Number of following tasks
a 4
b 3
c 2
d 2
e 1
f 1
g 0
D) for the idle time from the assigned tasks in "c" above, from the "image 2" attached; the percentage of the idle time will be=
Total remaining time of tasks without remaining feasibility tasks/ {(number of these tasks) x(CT)}
Which gives percentage of idle time = (0.8 + 0.8 + 0.8 + 1.0)/{(4)x(2)}
= 3.4/8 = 42.5%
Since we are to convert to decimal,
= 0.425 approximately 0.43
