Question

Someone anybody please help

Answer 1

This is a system of equations problem that can be solved using one of three methods: graphing, substitution, or elimination. I'll be using substitution.

In substitution:
1) Solve one equation for either variable. I'll use the first equation because its easier to solve for one of the variables. I'll be solving for y because that will allow us to solve for the value of x faster.
$x+y=60$
$y=60-x$

2) Substitute what you get into the other equation:
$20x + 5y = 600$
$20x + 5(60-x) = 600$

3) Solve your new equation in step 2 for the variable, x.
$20x + 5(60-x) = 600$
$20x + 300-5x = 600$
$15x + 300 = 600$
$15x = 300$ 
$x=20$

There are D) 20 $20 bills in her drawer.