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Lady_Fox [76]
3 years ago
7

I need help thank you

Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0

Answer:

1) k = 3

2) 3, 4, 5

3) k + (k + 2) + (k + 4) = 4k

4) 6, 8, 10

Step-by-step explanation:

Jared used the equation;

k + (k + 1) + (k + 2) = 4k

Let's find k.

3k + 3 = 4k

4k - 3k = 3

k = 3

Thus,the integers will be;

3, (3 + 1) and (3 + 2)

This is; 3, 4, 5

He is looking for consecutive even integers but yet got 3 and 5 which are odd numbers. However, he should have used the format;

k, (k + 2), (k + 4) as the 3 consecutive even integers.

Thus, rewriting the main equation gives;

k + k + 2 + k + 4 = 4k

3k + 6 = 4k

4k - 3k = 6

k = 6

Thus,the integers are;

6, (6 + 2), (6 + 4)

This is; 6, 8, 10

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