Answer:
-5 when ...
Step-by-step explanation:
The rules of exponents can help you simplify the given product.
<h3>Rules</h3>
(a/b)^c = (a^c)/(b^c)
(ab)^c = (a^c)(b^c)
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
<h3>Application</h3>

This expression does not match any of those offered.
When x=-1 and y=5, this becomes ...

Answer:
x-intercepts: (2, 0) and (−5, 0)
y-intercept: (0, −10)
Step-by-step explanation:
y = x^2 + 3x − 10
y-intercept when x = 0 so y = -10, so y-intercept : (0, -10))
x-intercept when y = 0 so
x^2 + 3x − 10 = 0
(x +5)(x - 2) = 0
x + 5 = 0; x = -5
x - 2 = 0; x = 2
So x-intercepts: (-5, 0) and (2,0)
Answer:
9.) The slope is 3 and the y-intercept is -5
10.) y = 0.25x -11
Hope this helped!
Stay safe! <3
Method OneYour calculator might be able to do this. Mine does it like this.
6
nCr
2
=
15
Method 2You could simply set up 6C2
This gives you
Method ThreeYou only have to do this a couple of times to see how the cancellation works.

After all the cancellation takes place you have
6*5/2 = 15
Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588