Answer:
17rx2−23rx−71x+75
Step-by-step explanation:
(17x−23)(xr−4)−(3x+17)
=(17x−23)(xr−4)+−1(3x+17)
=(17x−23)(xr−4)+−1(3x)+(−1)(17)
=(17x−23)(xr−4)+−3x+−17
=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17
=17rx2+−68x+−23rx+92+−3x+−17
=17rx2+−68x+−23rx+92+−3x+−17
=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)
=17rx2+−23rx+−71x+75
Answer:
a+0= a
Step-by-step explanation:
we know that
The <u>additive identity</u> property says that if you add a real number to zero or add zero to a real number, then you get the same real number back
so
Let
a -----> a real number
a+0=0+a=a
therefore
a+0= a
Answer:
73
Step-by-step explanation:
72 - 35 = 107
180 - 107 = 73
107 + 73 = 180
Answer:
first one
Step-by-step explanation: doesnt mention the number 8 variable anywhere
So since the shipping box is 3 / 3 1/4 you can fit 6 1/4 ÷ 2/4
