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allochka39001 [22]
3 years ago
13

Solve 2x − 1 = 11 for x using the change of base formula log base b of y equals log y over log b.

Mathematics
1 answer:
rosijanka [135]3 years ago
3 0

I think your equation is 2^{x-1} = 11

Answer:

x=4.459

Step-by-step explanation:

To solve the equation take natural log on both sides of equation:

(x-1)ln(2)=ln(11)         (∵  log(a^{b} )= b \times log(a) )

x - 1=ln(11)/ln(2)

(remember ln and log_{e} are same)

using base changing property:

x-1=log_{2} (11)       (∵ \frac{log_{e}(11) }{log_{e}(2)} = log_{2}(11))

x=log_{2}(11)+1

x=4.459

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The bounds for a discrete brownian walk is [-3, 4]. What is the expected value of the escaped time?
ch4aika [34]

11 is the expected value of the escaped time.

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= 4 - 0 + 4+3 = 11

Escape time refers to the time available (and necessary) for a person to escape from a particularly dangerous situation.

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7 0
2 years ago
How to solve this problem?
valentinak56 [21]

Very nice handwriting but the math and English are confusing.

Let's assume we're told

\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2

The subscript is important.

I think we're told the similar sum with 11 gives the smallest possible value for the sum. This is a rather cagey way of telling us 11 is the mean of the nine points. The mean is the number which minimizes the sum of squared deviations.

\displaystyle 45 = \sum_{i=1}^9 (x_i - 10)^2 = \sum x_i^2 - 20 \sum x_i + 9(100)

\displaystyle  \sum x_i^2=  20 \sum x_i  - 900

If 11 is the mean, the sum of the points is 9(11)=99.

\displaystyle  \sum x_i^2=  20 (99)  - 900 = 1080

Answer: 1080

6 0
3 years ago
A bag contains five tokens numbered 2, 3, 6, 7, and 8. Two tokens are taken in succession out of the bag without replacement. A)
Mice21 [21]

Answer and Step-by-step explanation:

A) Probability of taken two odd numbered token without replacement:

P(3) = 2/5 = 0.4

P(7) = 1/4 = 0.25

Construct a probability distribution:

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p(X)      0.4      0.25

B) Mean of the probability distribution:

E(X) = ∑xp

E(X) = 3*0.4 + 7*0.25

E(X) = 2.95

Variance of the probability distribution:

V(X) = \Sigma X^{2}p - [E(X)]^{2}

V(X) = 3^{2}*0.4+7^{2}*0.25 - (2.95)^{2}

V(X) = 7.1475

<u>Mean</u><u> and </u><u>variance</u><u> of the probability distribution are </u><u>2.95</u><u> and </u><u>7.145</u><u>, respectively.</u>

3 0
3 years ago
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