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denis-greek [22]
3 years ago
10

What is the value of X?what is the value of Y?​I will also give branliest

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0

Answer:

what is the value of X? 23

const2013 [10]3 years ago
5 0

Answer:

Step-by-step explanation:

The ratio of sides for the 30/60/90 triangle is 1:3^(1/2):2

Since the side opposite the 60 degree angle is 7(3^(1/2))

x=7(1)=7

y=7(2)=14

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Which is larger 1 1/2 or 1 15/16
solniwko [45]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

1 (15/16)

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Converting the Fractions...}}\\\\\rightarrow \frac{1}{2}=\frac{1*8}{2*8}=  \boxed{\frac{8}{16}}\\\\\text{We would only compare the fractions because we have the same whole number.}\\\\\frac{8}{16} 1\frac{1}{2}}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

6 0
3 years ago
Read 2 more answers
What is the product of (-3s+2t(4s-t)
galben [10]
Use the FOLD method<span>
(a+b)(c+d)=ac+ad+bc+bd

</span><span>−12<span>s<span><span>​^2 </span><span>​​</span></span></span>+ 3st + 8ts − 2<span>t<span><span>​^2</span><span>​​

</span></span></span></span>Collect like terms
-12{s}^{2}+(3st+8st)-2{t}^{2}

Simplify
<span>-12{s}^{2}+11st-2{t}^{2}<span>−12<span>s<span><span>​2</span><span>​​</span></span></span>+11st−2<span>t<span>​<span>2

The answer is = -12s^2 + 11st - 2t^2</span></span></span></span></span>
5 0
3 years ago
I need help on this problem.
aliya0001 [1]

In this situation, x=2.

5 0
3 years ago
1) Explain the Distributive Property in your own words.
kenny6666 [7]

Answer:

The Distributive Property states that when a number in parentheses is next to a number, you distribute the number outside of the parentheses and multiply by each of the numbers in parentheses.

5(10+x)=5(10)+5(x)=50+5x

:)

6 0
3 years ago
What is the image point of (-7,7) after a translation right 1 unit and down 3 units?
ZanzabumX [31]

Answer:

(-6, 4)

Step-by-step explanation

translation rule: (x+1,y-3)

(-7+1, 7-3)

(-6, 4)

6 0
3 years ago
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