Hello there.
<span>Square root of 41!?!?!??
</span><span>6.40312424 </span>
X, X+2, X+4 ARE THE 3 POSITIVE CONSECUTIVE INTEGERS.
X(X+2)=8+38(X+4)
X^2+2X=8+38X+152
X^2+2X-38X-8-152=0
X^2-36X-160=0
(X-40)(X+4)=0
X-40=0
X=40 ANSWER FOR THE FIRST INTEGER.
40+2=42 FOR THE SECOND INTEGER.
Answer:
23
Step-by-step explanation:
Answer:
I don't know your answer options, but this is what the graph would look like:
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