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olchik [2.2K]
2 years ago
11

At a particular restaurant, 62% of all customers order an appetizer and 41% of all customers order dessert. If 69% of all custom

ers order an appetizer or dessert (or both), what is the probability a randomly selected customer orders both an appetizer and dessert
Mathematics
1 answer:
jekas [21]2 years ago
5 0

Answer:

In terms of probablity (A - appetizer oredered, B - desert ordered)

P(A)=63%

P(B)=40%

P(AorB)=76%.

Using the formula:

P(AorB)=P(A)+P(B)-P(A&B) we get P(A&B)=63%+40%-76%=27% (probability we were looking for).

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Let n = number of records.

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She spent a total of $24, so 3n + 3 must equal 24. That gives us the following equation.

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3 years ago
Brain bought 2 shirts for 14.50 each and a pair of shoes for 29.99 the sales tax was 6%
Sedbober [7]
Cost of each shirt bought by Brain = 14.50
Then
Cost of 2 shirts bought by Brain = 2 * 14.50
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Total amount spent by Brain before tax = 29 + 29.99
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Percentage of sales tax that needs to be paid = 6%
Amount of sales tax that needs to be [paid = (6/100) * 58.99
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So
the total amount spent by Brain including tax = 58.99 + 3.54
                                                                         = 62.53
I hope this is the answer you were looking for.
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Answer:

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Step-by-step explanation:

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