At a particular restaurant, 62% of all customers order an appetizer and 41% of all customers order dessert. If 69% of all custom
ers order an appetizer or dessert (or both), what is the probability a randomly selected customer orders both an appetizer and dessert
1 answer:
Answer:
In terms of probablity (A - appetizer oredered, B - desert ordered)
P(A)=63%
P(B)=40%
P(AorB)=76%.
Using the formula:
P(AorB)=P(A)+P(B)-P(A&B) we get P(A&B)=63%+40%-76%=27% (probability we were looking for).
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