Write each rate as a unit rate 40.8 gallons in 8 containers

Find the Fourier series of a 1 V pulse train with a 10 percent duty cycle and a period of 1 ms. In other words, this signal cons

MArishka [77]

Answer:

The answer is attached below

Step-by-step explanation:

8 0

3 years ago

Example 1: Calculation of Normal Probabilities Using ????????-Scores and Tables of Standard Normal Areas The U.S. Department of

Molodets [167]

Answer:

i) 0.872

ii) 0.300

iii) 0.76

iv) 0.704

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $261.50 per month

Standard Deviation, σ = $16.25

We are given that the distribution of monthly food cost for a 14- to 18-year-old male is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(Less than $280)

$P( x < 280) = P( z < \displaystyle\frac{280 - 261.50}{16.25}) = P(z< 1.138)$

Calculation the value from standard normal z table, we have,

$P(x < 280) = 0.872 = 87.2\%$

b) P(More than $270)

P(x > 270)

$P( x > 270) = P( z > \displaystyle\frac{270 - 261.50}{16.25}) = P(z > 0.523)$

$= 1 - P(z \leq 0.523)$

Calculation the value from standard normal z table, we have,

$P(x > 270) = 1 - 0.700 = 0.300 = 30.0\%$

c) P(More than $250)

P(x > 250)

$P( x > 250) = P( z > \displaystyle\frac{250 - 261.50}{16.25}) = P(z > -0.707)$

$= 1 - P(z \leq -0.707)$

Calculation the value from standard normal z table, we have,

$P(x > 250) = 1 - 0.240 = 0.76 = 76.0\%$

d) P(Between $240 and $275)

$P(240 \leq x \leq 275) = P(\displaystyle\frac{240 - 261.50}{16.25} \leq z \leq \displaystyle\frac{275-261.50}{16.25}) = P(-1.323 \leq z \leq 0.8307)\\\\= P(z \leq 0.8307) - P(z < -1.323)\\= 0.797 - 0.093 = 0.704 = 70.4\%$

$P(240 \leq x \leq 275) = 70.4\%$

e) Thus, 0.704 is the probability that the monthly food cost for a randomly selected 14- to 18-year-old male is between $240 and $275.

5 0

3 years ago

What is the factors of x^2-16x+64

ddd [48]

Answer:

(x-8)² or (x-8)(x-8)

Step-by-step explanation:

7 0

3 years ago

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What is bigger 7/8 or 14/15

GalinKa [24]

14/15 is .93333333333333333 and 7/8 is .875 so 14/15 is
bigger

8 0

3 years ago

For the following exercises, determine the point(s), if any, at which each function is discontinuous. Classify any discontinuity

NARA [144]

Answer: (a). at x = 0, its a removable discontinuity

and at x = 1, it is a jump discontinuity

(b). at x = -3, it is removable discontinuity

also at x = -2, it is an infinite discontinuity

(c). at x = 2, it is a jump discontinuity

Step-by-step explanation:

in this question, we would analyze the 3 options to determine which points gave us discontinuous in the category of discontinuity as jump, removable, infinite, etc.

(a). given that f(x) = x/x² -x

this shows a discontinuous function, because we can see that the denominator equals zero i.e.

x² - x = 0

x(x-1) = 0

where x = 0 or x = 1.

since x = 0 and x = 1, f(x) is a discontinuous function.

let us analyze the function once more we have that

f(x) = x/x²-x = x/x(x-1) = 1/x-1

from 1/x-1 we have that x = 1 which shows a Jump discontinuity

also x = 0, this also shows a removable discontinuity.

(b). we have that f(x) = x+3 / x² +5x + 6

we simplify as

f(x) = x + 3 / (x + 3)(x + 2)

where x = -3, and x = -2 shows it is discontinuous.

from f(x) = x + 3 / (x + 3)(x + 2) = 1/x+2

x = -3 is a removable discontinuity

also x = -2 is an infinite discontinuity

(c). given that f(x) = │x -2│/ x - 2

from basic knowledge in modulus of a function,

│x│= │x x ˃ 0 and at │-x x ∠ 0

therefore, │x - 2│= at │x - 2, x ˃ 0 and at │-(x - 2) x ∠ 2

so the function f(x) = at│ 1, x ˃ 2 and at │-1, x ∠ 2

∴ at x = 2 , the we have a Jump discontinuity.

NB. the figure uploaded below is a diagrammatic sketch of each of the function in the question.

cheers i hope this helps.

3 0

3 years ago

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