Answer:
the first formula
Step-by-step explanation:
the graph is y=cosx and cosx=sin(x+90)
Answer:
a.2nd quarter with 9 goals
b. 4.8 goals
c. 4 goals
Step-by-step explanation:
a. The mode is defined as the most appearing data point or the data point with the highest frequency..
From our data(for away goals):
- 1st quarter-2
- 2nd quarter-9
- 3rd quarter-7
- 4th quarter-4
Hence, the 2nd quarter has the mode for away goals with 9 goals.
b. Mean is defined as the average of a set of data points.
#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:
![\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%7Bx_i%7D%5C%5C1%5E%7Bst%20%7D_g%3DAway%2BHome%3D5%2B2%3D7%5C%5C%5C%5C2%5E%7Bnd%7D_g%3DAway%2BHome%3D4%2B9%3D13%5C%5C%5C%5C3%5E%7Brd%7D_g%3DAway%2BHome%3D8%2B7%3D15%5C%5C%5C%5C4%5E%7Bth%7D_g%3DAway%2BHome%3D9%2B4%3D13%5C%5C%5C%5C%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%7Bx_i%7D%3D%5Cfrac%7B1%7D%7B10%7D%287%2B13%2B15%2B13%29%3D4.8)
Hence, the mean number of goals per quarter is 4.8 goals
c. To find the number of more home goals than away goals, we subtract from their summations as:
![g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4](https://tex.z-dn.net/?f=g_m%3D%5Csum%7Bg_h%7D-%5Csum%7Bg_a%7D%5C%5C%5C%5C%3D%285%2B4%2B8%2B9%29-%282%2B9%2B7%2B4%29%5C%5C%5C%5C%3D26-22%5C%5C%5C%5C%3D4)
Hence, there are 4 more home goals than away goals.
<ADB = 90 degrees
hope it helps
x-32.2= 18.5
Add 32.2 to both sides
x-32.2+32.2 = 18.5 + 32.2
x = 50.7
I hope that's help !
Check your answer
replace x by its number
50.7-32.2= 18.5
18.5 = 18.5
so the answer is good .
Please let me know if you have question(s) !