Least to greatest -4.3, -82.5, -41 4/5, -13 1/8

Mathematics

1 answer:

kicyunya [14]4 years ago

5 0

-82.5, -41 4/5, -13 1/8, -4.3

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Check my math work please, use photo attached

Sonja [21]

Answer:

The department total on the bottom right hand side should be 464253. Everything else is correct.

Step-by-step explanation:

Adding was wrong across the bottom row.

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3 years ago

Yesterday , the snow was 2 feet deep in front of archies house. Today, the snow depth dropped to 1.6 feet because the day is so

olga55 [171]

Earlier snow depth = 2 feet
later snow depth = 1.6 feet

change
2 - 1.6
0.4 feet

percentage change
(0.4 / 2) * 100
20 %

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4 years ago

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Anton [14]

Answer:

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3 years ago

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$