Tabitha Tidbits costs $7 per bag, and Figaro Flakes is $5.50 per bag.
You need to set up a system of equations. Use "x" for Tabitha Tidbits and "y" for Figaro Flakes, and let the total cost of each trip equal c. Using the equation ax+by=c, substitute the cost of each trip in for c, and the number of bags for each food for a and b respectively. The two equations will be:
3x+4y=43
3x+6y=54
Isolate x in the first equation and you will get:
x=(43-4y)/3
Substitute the above equation for x into the other equation:
3*((43-4y)/3)+6y=54
Isolate y in this equation, and you will get 11/2, which is 5.5
So the cost of one bag of Figaro Flakes is $5.50
Now substitute this into the equation where you isolated x:
(43-4(5.5))/3
You will get x=7, so a bag of Tabitha Tidbits is $7
If you would like to know how many papers will be missing the name, you can calculate this using the following steps:
30% of 200 homework papers = 30% * 200 = 30/100 * 200 = 60 homework papers
The correct result would be a) between 50 and 70 papers will be missing the name.
We are given
P = $754.43
r = 13.6% annual
for a.
A = 150
for b.
A = 300
First, change the interest into effective monthly
i = (1 + 0.136/12)^12 - 1
Solve for i
Next, use the general formula
A = P i ( 1 + i)^n / (1 + 1)^n - 1
Subsitute P, i, and A for a and b.
Then, solve for n for a and b.
Yellow :) & yes, hope your day is good
