Hello,
John : n
Brad : n + 12
n + n + 12 = 84
2n + 12 = 84
2n = 84 - 12
2n = 72
n = 72/2
n = 36
John $36 and Brad $36 + $12 = $48
Answer:
<h2>D.</h2>
Step-by-step explanation:
<h2>BEACAUSE ITS FORMED PROPERLY</h2>
Y2 - y1 over x2 - x1 = slope
2 - (-1) = 3
-1 - 2 = -3
the slope is 3/-3, or -1
y = -x
2 = 1 + 1
The equation of the line is y = -x + 1
We can use the Сosine formula to solve this problem.
<span>First we must find the third side (АС) of the triangle:
</span>

<span>
The smallest angle of the triangle lies opposite the smallest side, so we need to find m</span>∠C.

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:
m∠С = 38°42' = 38.7°
Answer: 38.7°
<span>I hope this helps</span>
Vertex form is given by:
y=a(x-h)^2+k
where the vertex is (h,k)
7. (h,k)=(-4,1)
plugging in the equation we get:
y=a(x+4)^2+1
but substituting (0,2) in the equation and solving for a we get:
2=a(0+4)^2+1
a=1/16
hence:
Answer: y=1/16(x+4)^2+1
8]
(h,k)=(2,-4)
thus
y=a(x-2)^2-4
plugging point (3,0) in the eqn and solving for a we get
0=a(3-2)^2-4
0=a-4
a=4
hence;
Answer: y=a(x-2)^2-4
9] (h,k)=(3,3)
thus;
y=a(x-3)^2+3
plugging (2,2) in the equation we get:
2=a(-1)^2+3
a=-1
thus;
Answer: y=-1(x-3)^2+3
10] (h,k)=(-1,-1)
y=a(x+1)^2-1
plugging (0,-3) in the equation and solving for a we get:
-3=a(1)^2-1
a=-2
thus
Answer: y=-2(x+1)^2-1
11] (h,k)=(1,2)
y=a(x-1)^2+2
plugging (0,4) in the equation and solving for a we get:
4=a(-1)^2+2
a=2
thus
y=2(x-1)^2+2
12] (h,k)=(3,-2)
y=a(x-3)^2-2
plugging (2,0) and solving for a we get:
0=a(2-3)^2-2
a=2
thus
t=2(x-3)^2-2