<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span>
<span>Trapezoid area = ((5 + 3) / 2) * 5
</span>
Trapezoid area = ((8) / 2) *5
<span>Trapezoid area = 20
Source:
http://www.1728.org/quadtrap.htm
</span>
Answer:
124
Step-by-step explanation:
First subtract 6 to both sides.
![\sqrt[5]{249-2x} = 1](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B249-2x%7D%20%3D%201)
Then take the 5th power of both sides to remove the radical.

Which is essentially:
-2x = 1 - 249
-2x = -248
Divide both sides by -2
x = 124
And there ya go :)
Answer:
45 meters
Step-by-step explanation:
If x represents the seconds after the launch, then the time of launch is when x=0 so you just need to solve for h(0)
h(0) = -5(1)(-9)
h(0) = 45
the answer for this question is (C)3