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polet [3.4K]
4 years ago
14

Given that a trapezoid has the following dimensions, find the area. Area = ________ units^2 (only put the number)

Mathematics
1 answer:
patriot [66]4 years ago
5 0
<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span>
<span>Trapezoid area = ((5 + 3) / 2) * 5
</span>
Trapezoid area = ((8) / 2) *5

<span>Trapezoid area = 20

Source:
http://www.1728.org/quadtrap.htm
</span>

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Identify a pair of vertical angles in the figure.<br>A. and B. and C. and D. and 
diamong [38]

Can i see the picture please nut if it was like mine i would say a

4 0
4 years ago
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 8x and y = 2x + 2 intersect are the so
OleMash [197]

The point of intersection of two given equations is (0.333, 2.667).

Given that, equation with two variables are y = 8x and y = 2x + 2.

The given equations will intersect at some point where y is the same for both equations.

When you replace y in y = 2x + 2 with y = 8x, we get 8x = 2x + 2.

So, the solution of 8x = 2x+2 will satisfy both equations.

Now, we need to find the solutions to take the integer values of x between -3 and 3.

That is,

x = -3 , then 8(-3) = 2(-3) +2⇒-24 = -6+2

⇒-12 = -4    False.

similarly, for x = -2

8(-2) = 2(-2)+2

⇒-16 = -2   False

For, x = -1

8(-1) = 2(-1)+2

⇒-8= 0   False

For, x = 0

8(0) = 2(0)+2

⇒0= 2   False

For, x = 1

8(1) = 2(1)+2

⇒8= 4   False

For, x = 2

8(2) = 2(2)+2

⇒16 = 6   False

For, x = 3

8(3) = 2(3)+2

⇒24 = 8   False

Therefore, there is no solution to 8x = 2x +2 for the integers values of x between -3 and 3.

The equations can be solved graphically by plotting the two given functions on a coordinate plane and identifying the point of intersection of the two graphs.

The point of intersection is the values of the variables which satisfy both equations at a particular point.

Hence, you can see the graph as shown below, the point of intersection is (0.333, 2.667).

To learn more about the graphical representation of equation visit:

brainly.com/question/12804458.

#SPJ1

3 0
2 years ago
Can some one help me on this and thank u
atroni [7]

Answer:

2<x<3

Step-by-step explanation:

the first one

5 0
3 years ago
How do you find the volume inside the cylinder but outside the sphere? H=12cm.
Mrrafil [7]
Apparently, there is a sphere inside a cylinder, and we need to find
(the volume of the cylinder) minus (the volume of the sphere).

This wouldn't be too awfully difficult if we had the measurements we need
in order to calculate the volume of the cylinder and the volume of the sphere. 
You did give us a number, thank you, but no description, so we don't even know
what's 12, because we don't know how 'H' figures into anything.

If you have the numbers, here are the formulas you'll need:

Volume of a cylinder = π (radius)² (height or length)

Volume of a sphere = (4/3) π (radius)³
===============================================
Oh I think I get it.  There's a little ball stuck inside a cylinder, they
both have the same radius, and the height of the cylinder is 12.

That's still not enough information to do a complete calculation.
I'm afraid we still need that radius.  But we can get closer:

Volume of the cylinder = π (radius)² (12)

Volume of the sphere = (4/3) π (radius)³

(Cylinder) minus (sphere) = (4/3) π (radius²) ( 9 - radius ) .

Stuff the number for the radius into that, and you'll have the answer.

And if you need it, remember, the radius is 1/2 of the diameter.
5 0
3 years ago
A triangular prism is shown.<br> What is the surface area of the triangular<br> prism?
Brilliant_brown [7]

Answer:

Area= 840

Step-by-step explanation:

Area= (20x13)x2+(10x12x1/2)x2+10x20

=520+120+200

=840

  • Area=Two area of the triangle [13x20] + Two area of the rectangle + Under area (rectangle)- [10x20]
5 0
3 years ago
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