3 years ago

64 = (3x+1) Find the value of x. A) 21 B) 27 C) 31 D) 34

1 answer:

7 0

Take away 1 from either side so the equation becomes 63=3x then divide both sides by 3 so it becomes 21=x which is your answer (option A)

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drek231 [11]

Answer:

$x_{2} = 0.0000$

Step-by-step explanation:

The formula for the Newton's method is:

$x_{i+1} = x_{i} + \frac{f(x_{i})}{f'(x_{i})}$

Where $f' (x_{i})$ is the first derivative of the function evaluated in $x_{i}$ .

$x_{i+1} = x_{i} + \frac{x_{i}^{4}-x_{i}-3}{4\cdot x_{i}^{3}-1}$

Lastly, the value of $x_{2}$ is determined by replacing $x_{1}$ with its numerical value:

$x_{2} = x_{1} + \frac{x_{1}^{4}-x_{1}-3}{4\cdot x_{1}^{3}-1}$

$x_{2} = 1.0000 + \frac{1.0000^{4}-1.0000-3}{4\cdot (1.0000)^{3}-1}$

$x_{2} = 0.0000$

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