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34kurt
3 years ago
8

Which of the following sets of numbers could not represent the three sides of a

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0
The Second Option I know im right
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Read 2 more answers
WILL MARK BRAINLIEST !!!<br> find the indicated value for each of the figures shown or described
timama [110]

Answer:

10. 9

In the first question we can solve using the Pythagorean theorem. It states that the hypotenuse in a right triangle or the longest side of the triangle, squared is equal to the other 2 sides, squared. Its expressed as so: C^2 = A^2 + b^2 where c is the hypotenuse and a and b are the other sides oft eh triangle.

Therefore,

15^2 = 12^2+x^2

225=144+x^2

81=x^2

x=9

__________________________________________________________

11. x=12

In this figure, there are 2 right triangles on the sides of the square. If we can find the lengths of the base of both triangles then we can find x using the Pythagorean theorem. the total base is 21 and the square is 11. 11+a+b=21. We can assume that both triangles are congruent and therefore we can solve this equation:

11+a+b=21

a+b=10

5+5=10

b=5

a=5

The bases of the two triangles are 5 and the hypotenuse is 13. Now we can solve using the Pythagorean theorem:

c^2 = a^2+b^2

13^2=5^2+x^2

169=25+x^2

144=x^2

144= 12 x 12

x=12

__________________________________________________________

12.

The diagnol of a triangle is the hypotenuse and since the length is the square root of 3, we have all the information we need.

c^2 = a^2+b^2

2^2 = (square root of 3)^2+b^2

4=3+b^2

1=b^2

b=1

Step-by-step explanation:

6 0
3 years ago
Write the equation of the line parallel to 4x-5y=2 and passing through point (0,0)
kotykmax [81]

k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2

We have:

4x-5y=2\ \ \ \ |-4x\\\\-5y=-4x+2\ \ \ \ |:(-5)\\\\y=\dfrac{4}{5}x-\dfrac{2}{5}\to m_1=\dfrac{4}{5}\\\\l:y=m_2x+b\\\\k\ \prep\ l\Rightarrow\dfrac{4}{5}m_2=-1\ \ \ \ |\cdot\dfrac{5}{4}\\\\m_2=-\dfrac{5}{4}

l:y=-\dfrac{5}{4}x+b

The line l is passing through point (0, 0). Substitute the coordinates of the point to the equation of a line l:

0=-\dfrac{5}{4}\cdot0+b\to b=0

y=-\dfrac{5}{4}x\ \ \ \ |\cdot4\\\\4y=-5x\ \ \ \ |+5x\\\\5x+4y=0

<h2>Answer: 5x + 4y = 0</h2>
8 0
3 years ago
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