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amm1812
2 years ago
9

De los 30 balones de un colegio, dos quintos son de fútbol, un tercio de baloncesto y el resto de voleibol. ¿Cuántos balones de

voleibol hay en el colegio? ayuda es para hoy ;(​
Mathematics
1 answer:
liraira [26]2 years ago
3 0

Answer:

Number of Volleyballs = 8 balls

Step-by-step explanation:

Given:

Total number of balls = 30 balls

Fraction of soccer ball = 2/5 balls

Fraction of basketball = 1/3 balls

Rest are Volleyballs

Find:

Number of Volleyballs

Computation:

Number of Volleyballs = Total number of balls - Total number soccer balls - Total number of basketballs  

Number of Volleyballs = 30 - (30)(2/5) - (30)(1/3)

Number of Volleyballs = 30 - 12 - 10

Number of Volleyballs = 30 - 22

Number of Volleyballs = 8 balls

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What Value of m will make this equation true? 3 (m - 5) + 8 = 7 - 1/2 (4m - 11)​
KatRina [158]

Answer:

m = 7.1

Step-by-step explanation:

3 (m -5) + 8 = 7 -1/2 (4m - 11)

So, what I did first was distribute the values in the parenthesis to get,

3m - 15 + 8 = 7 -2m -5.5

Now that we have the parenthesis taken care of we can do the simpler math,

3m - 23 = 7 -2m - 5.5

I just added the 15 and 8, so now I move the -5.5 to the opposite side by adding.

3m - 23 = 7 -2m -5.5

<u>        +5.5             +5.5</u>

3m - 28.5 = 7 - 2m

Here we can do the same with the -2m.

3m - 28.5 = 7 - 2m

<u>+2m                 +2m</u>

5m - 28.5 = 7

To get rid of the -28.5 I added it to the 7 getting an answer of,

5m - 28.5 = 7

<u>      + 28.5    +28.5</u>

5m = 35.5

Finally, divide 5m and 35.5 both by 5.

5m/5 = m

35.5/5 = 7.1

Answer: m=7.1

Sorry it's really long, but I hope this helps! Have a great day!

6 0
3 years ago
Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

#SPJ1

7 0
2 years ago
14
Nuetrik [128]

Answer:

Distance LM = 5.20 unit (Approx.)

Step-by-step explanation:

Given coordinates;

L(1, 4, 7) and M(2, 9, 8)

Find:

Distance LM

Computation:

Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²

Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²

Distance LM = √(1)² + (5)² + (1)²

Distance LM = √1 + 25 + 1

Distance LM = √27

Distance LM = 3√3 unit

Distance LM = 3(1.732)

Distance LM = 5.196

Distance LM = 5.20 unit (Approx.)

5 0
3 years ago
Rewrite the equation by completing the square.<br> x^2+ 4x = 0
ExtremeBDS [4]

Answer:

Here you go

Step-by-step explanation:

x=0,-4

3 0
2 years ago
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A Euler circuit has ___ ODD vertices
xenn [34]

Answer:

A Euler circuit has TWO ODD vertices

Step-by-step explanation:

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3 years ago
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